Find sampling interval - horizontal and vertical asymptote, Mathematics

In a digital filter, one of the parameters in its difference equation is given by the formula

1637_Find Sampling Interval.png

a) Show that the above formula has one horizontal and one vertical asymptote.

b) show that the graph of 11 against x passes through the origin'

c) By attempting to find the turning points of the above function, show that there aren't any.

d) Sketch the graph of Y against x.

e) From the resulting sketch, find:

i) The value that y approaches to whenever r increases to a very large number.

ii) The sampling interval T if, as the parameter y increases, x is required to approach the value -2.

Posted Date: 3/2/2013 7:35:09 AM | Location : United States







Related Discussions:- Find sampling interval - horizontal and vertical asymptote, Assignment Help, Ask Question on Find sampling interval - horizontal and vertical asymptote, Get Answer, Expert's Help, Find sampling interval - horizontal and vertical asymptote Discussions

Write discussion on Find sampling interval - horizontal and vertical asymptote
Your posts are moderated
Related Questions
one bathroom is 0.3m long how long is a row of 8 tiles

Hypothesis Testing Of The Difference Between Proportions Illustration Ken industrial producer have manufacture a perfume termed as "fianchetto." In order to test its popul

what is the importance of solid mensuration?

Calculate Moving Average The table given below represents company sales; calculate 3 and 6 monthly moving averages, for data Months Sales

Define tautology and contradiction.  Ans: If a compound proposition comprises two atomic propositions as components, after that the truth table for the compound proposition con

Solving Trig Equations with Calculators, Part I : The single problem along with the equations we solved out in there is that they pretty much all had solutions which came from a


Divergence Test Once again, do NOT misuse this test.  This test only says that a series is definite to diverge if the series terms do not go to zero in the limit.  If the

Solve 4 sin 2 ( t ) - 3 sin ( t /3)= 1 . Solution Before solving this equation let's solve clearly unrelated equation. 4x 2 - 3x = 1  ⇒ 4x 2 - 3x -1 = ( 4x + 1) ( x

Five years ago a business borrowed $100,000 agreeing to repay the principal and all accumulated interest at 8% pa compounded quarterly, 8 years from the loan date. Two years after