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Find out the x-intercepts & y-intercepts for each of the following equations.
y =x2 +x - 6
Solution
As verification for each of these we will also sketch the graph of each of function. We will leave the details of the sketching to you to determine.
y = x2 + x - 6
Let's first determine the y-intercept(s). Again, we do this by setting x = 0 & solving for y. usually this is the easier of the two. Thus, let's determine the y-intercept(s).
y =(0)2 + 0 - 6 = -6
Thus, there is a single y-intercept : (0, -6) .
The work for the x-intercept(s) is approximately identical except in this case we set y = 0 and solve for x. Following is that work.
0 =x2 + x - 6
0 = (x + 3) (x - 2)
⇒ x =- 3, x = 2
For this equation there are two x-intercepts: (-3, 0) & (2, 0) .
For verification reason here is sketch of the graph for this equation.
Find the normalized differential equation which has {x, xex} as its fundamental set
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compare: 643,251: 633,512: 633,893. The answer is 633,512.
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