Fatigue crack propagation, Mechanical Engineering

Fatigue crack propagation:

If it is assumed that no plastic deformation occurs around crack tip and law of fatigue crack propagation for place of above Example is da/dN =  10- 8 (Δ KI eff )2.0 mm/cycle , find after how many cycles the plate will fracture.

Solution

Δ K I = ΔK I eff     because there is no plastic deformation in crack tip neighbourhood.

1926_Fatigue crack propagation.png

ac = 146.14 mm, ai = 35 mm from above Example .

or, Nf   =2´104 ln ( ac/ ai) =  2´104 ln (146.14/35)

or, N f  = 2´104 ln (4.175) = 28584 cycles

Posted Date: 1/23/2013 3:07:47 AM | Location : United States







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