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Express the GCD of 48 and 18 as a linear combination. (Ans: Not unique)
A=bq+r, where o ≤ r < b
∴ HCF (18,48) = 6
now 6= 18-12x1
i.e. 6= 18x +48y
∴ x=3 , y=-1
6= 18×3 +48×(-1)
=18×3 +48×(-1) + 18×48-18×48
∴ x = 51, y = -19
Hence, x and y are not unique.
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