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Explain the number unobtainable tone in strowger telephony with waveforms and the timings.
In the following figure illustrates the number unobtainable tone that is continuous 400 Hz signal. This tone might be sent to the calling subscriber because of a variety of reasons as the called party line is out of order or disconnected, and an error in dialing leading to the selection of a spare line. In the several exchanges the number unobtainable tone is 400 Hz intermittent along with 2.5 s on period and 0.5 s off period.
Figure: the number unobtainable tone
Define pipeline speedup. S(m)=T(l)/T(m) Where T(m) is the execution time for some target workload on an m-stage pipeline. T(l) is the execution time for some workload an
Can you tell me some of system tasks and their purpose? $display, $displayb, $displayh, $displayo, $write, $writeb, $writeh, $writeo. The most useful of these is $display. T
Program generation activity aims at? Ans. At automatic generation of program the program generation activity aims.
Implementing Protection with Virtual Memory - computer architecture: To enable the operating system to implement protection in the VM system, the HW have to: I. Support at
Q. What is the working of domain expert? ANSWER: The domain expert is the person who gives the domain expertise in the form of problem-solving strategies.
Q. How to calculate Colour Depth? Colour Depth (or number of Colour Planes) is number of bits assigned to every pixel to code colour information in it. These are also known as
Application Using Shift Operations Rotate and Shift instructions are helpful even for division andmultiplication. These operations are not normally available in high-level lang
What is double data rate SDRAM? Double data rates SDRAM are those which can transfer data on both edges of the clock and their bandwidth is fundamentally doubled for long burs
Determine about the Radio Frequency (RFID) This method includes using small electronic devices containing an Identification microchip and antenna; they work in a similar way
Which of the memories stores the most number of bits ? Ans. most number of bits stores in 32M x 8 As 2 5 x 2 20 = 2 25 Therefore 1M = 2 20 = 1K x 1K = 2 10 x 2 10
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