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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
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Hi there I am looking for help with c++ coursework. Could you please provide me with email address to email a copy of it. Thanks
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(a) Write a procedure called (mult x y) that multiplies two numbers x and y in a recursive manner using successive addition. Specifically, note that a x b = a + a + .... + a (b tim
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