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The continue statement
The continue statement causes the next iteration of the enclosing loop to start. When this is encountered in the loop , the rest of the statements in the loop are leave out and control passes to the condition.
Let us see an example that accepts a variable amount of numbers from the keyboard and prints the sum of only positive numbers.
e.g.
void main()
{
int num, total = 0;
do
cout << " enter 0 to quit ";
cin >> num; // equivalent to scanf()
if(num == 0)
break;
if(num < 0)
continue;
total+=num;
}
while(1);
cout << total;
one of the segments is showing compilation error...
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#include stdio.h> #include conio.h> #include string.h> void main() { int i=0,j=0,k=0,l=0; int a[3][3],temp[3][3]; clrscr();
A: No. If they're utilized properly, they increase encapsulation. You frequently require splitting a class in half while the two halves will have distinct numbers of instances o
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A: They are following: Const: point out that memory once initialized, must not be modify through a program. Volatile: denote that value in the memory location can be modified
what is virtual datatype
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