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The rPeANUt simulator provides buffering of the characters that are typed into the terminal. However, this would generally not be the case so if the program did not consume a character before the next one is typed then a character may be lost. So in this next part of the lab you are required to write an interrupt handler for the IO terminal that will capture characters as they are typed and place them in a buffer. The read system call would then read them out of this buffer rather than directly from the device. The psudo code for interrupt handler with a single character buffer:
void iohandler () {
if (buffcount == 0) {
buff = getchar(); // no need to poll on the status register
buffcount = 1;
} else {
getchar(); // no room in the buffer so we lost a character!!!
}
enableInterrupts();
void traphandler () {
enableInterruptes();
if (R0 == 0) { // read system call
while (buffcount == 0) ;
R1 = buff;
buffcount = 0;
} else if (R0 == 1) { // write system call
putchar(R1); // just store R1 to memory location 0xfff0
char buff;
int buffcount;
void main() {
enableIOterminalInterrupts(); // involves writing to the control register of the IO terminal device.
char c;
while (1) {
c = read();
write(c);
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">http://www.ee.nmt.edu/~erives/289_F12/EE289_Takehome_2.pdf http://www.ee.nmt.edu/~erives/289_F12/Takehome2_maze.GIF
1.jewels can only be removed for polishing from either end of the necklace. 2.cost of polishing=sitting number*colour value of jewels.
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This program requires the use of a windows box, no console applications are allowed. Prepare for Christmas now. Each year, Reindeer Gift Emporium publishes a Christmas price list
I want to take 1.1 as input but when I am declaring it as float the output is given as 1.1000000
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