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Additional-reference-bits algorithm
We can keep an 8-bit byte for every page in a table in memory. The operating system shifts the reference bits right 1 bit, discarding the low-order bit. These 8 bits sift register have the history of page used for previous eight time periods. A page with a history value of 11000100 has been used more just than has one with 01110111. The page with the lowest number is the LRU page, and it can be changed.
Q. What are the reasons for process suspension? Reasons for process suspension 1. Swapping 2. Timing 3. Interactive user request 4. Parent process request
CONTROL PROGRAMS Control Programs are those programs which control & maintain the operation of computer. They provide basic facilities. Control program are further divided into
Most process abstractions support processes being destroyed when the program terminates, or in response to a specific kill directive. There are two common implementations, one a "p
VARIABLE PARTITIONING We can differ the partitions and change the location according to the size of the process. Here if a 10k process enters we are able to make a space of
Garbage collectors trade space for time. If we collect all the time (which requires a lot of processing time), the GC allocator will use the least memory possible. On the other han
Define thread cancellation & target thread. The thread cancellation is the task of terminating a thread before it has completed. A thread that is to be cancelled is often refer
Ask question Project Details PROJECT OVERVIEW The ABC Hospital is upgrading their version of Windows. As part of the upgrade, 100 new computers will be purchased. Your task is to
List two types of system directories A) Device directory:- Describing physical properties of files. B) File directory :- Giving logical properties of the files.
What is preallocation? Why do it? Allocating space for a file before making the file to allow for expansion. This reserves space for a certain file so that other files can't gr
The following is a dump of a TCP header in hexadecimal format: 00CD0018 00000EF1 00000D5D 502200D1 01BF0010 We need to first split the above hex as such 00 CD 00 18 00 00
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