Evaluate the area of the shaded region, Mathematics

 Using the example provided, Evaluate the area of the shaded region in terms of π.

1690_Evaluate the area of the shaded region.png

a. 264 - 18π

b. 264 - 36π

c. 264 - 12π

d. 18π- 264

b. The area of the shaded region is the area of a rectangle, 22 by 12, minus the area of a circle with a radius of 6. The area of the rectangle is (22)(12) = 264. The area of a circle with radius 6 and a radius of 6, is π(6)2 = 36π. The area of the shaded region is 264 - 36π. If you select a, the formula for area of a circle was incorrect, 1 πr2. If you select c, the formula for area of a circle was incorrect, πd. If you select d, this was the reverse of choice a-area of the circle minus area of the rectangle.

Posted Date: 5/24/2013 3:41:10 AM | Location : United States







Related Discussions:- Evaluate the area of the shaded region, Assignment Help, Ask Question on Evaluate the area of the shaded region, Get Answer, Expert's Help, Evaluate the area of the shaded region Discussions

Write discussion on Evaluate the area of the shaded region
Your posts are moderated
Related Questions
joey asked 30 randomly selected students if they drank milk, juice, or bottled water with their lunch. He found that 9 drank milk, 16 drank juice, and 5 drank bottled water. If the

If α, β are the zeros of the polynomial x 2 +8x +6 frame a Quadratic polynomial whose zeros are a)  1/α and  1/β b) 1+ β/α , 1+ α/β. Ans. P(x) = x 2 +8x +6 α + β = -8

limit 0 to 2(3x^2+2) Solution) integrate 3x^2 to x^3 and 2 to 2x and apply the limit from 0 to 2 answer is 12.

in right angle triangle BAC.

Alternating Series Test - Sequences and Series The final two tests that we looked at for series convergence has needed that all the terms in the series be positive.  Actually t


howwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwwww

A rectangles lenth is (x+4) and width is (x+3).By adding binomials give its perimiter

Taking 2^x=m and solving the quadratic for getting D>=0 we get range= [3/4 , infinity )