Electromagnetic conversion device with example., Mechanical Engineering

Assignment Help:

Q. In every electromagnetic conversion device, both generator and motor action take place simultaneously. Explain.

The case the output is mechanical as in a motoring mode, the coupling field must react with the electrical system as to absorb electrical energy from electrical system. In such a case i.e. in a motoring mode this reaction is counter emf e , similar to the emf induced in the primary winding of a transformer the coupling field extracts energy proportional to ei from the electrical system, converts it into mechanical from and delivers energy proportional to T? to the mechanical system.

In case the output is electrical as in a generating mode, the coupling field must react with mechanical system so as to absorb mechanical energy from mechanical system. In such a case ei, in a generating mode, this reaction is the counter torque T developed due to interactions of current i and the coupling field. Thus coupling field extracts mechanical energy proportional to T? from the mechanical system converts into electrical form and delivers energy proportional to ei to the electrical system.

Example

A coil with an axial length of 25 cm and diameter of 20 cm has 200 turns. It is placed in a uniform radial flux of 0.002 web/m2/ (a) If the coil is rotated at 25 rev. per sec., find the voltage induced in the coil. (b) What will be the force on each conductor and torque acting on the coil, if it carries a current of 10 Amps.

 l = 25 cm

 

            d = 20 cm

 

            N = 200 turn

 

            Φ = 0.002 ?b/m2

 

            V = 25 rev. per sec.

 

             e = T

 

             e = Blv

 

            B =  Φ/a

 

             a = π/4 (d2) = π/4 × (20 × 10-2)2 = 0.0314 m2

 

            B = 0.002/0.0314 T

 

            B = 0.06269 T

 

             e = 0.06363 × (25 × 10-2) × 25

 

             e = 0.398

 

             e = 0.4 volts

 

             f = BIl

 

            F = 0.06369 × 10 × 25 × 10-2 = 0.159225 newtons

 

            T = 2 IBRl

 

 

               = 2 × 10 × 0.06369 × 20/2 × 10-2 × 25 × 10-2 = 0.031845 N-m


Related Discussions:- Electromagnetic conversion device with example.

Access considerations for plant design, Q. Access Considerations for plant ...

Q. Access Considerations for plant design? Plant facilities shall be provided with acceptable access and egress for personnel, materials, and equipment by using access ways, ro

Compression ignition engines - thermodynamics, Compressio n Ignition Engin...

Compressio n Ignition Engines (or C.I. Engine): It works on the basis of dieses cycle. In diesel engines, energy addition occurs at constant pressure but energy rejection at

When was pddi developed, When was PDDI developed The PDDI interface was...

When was PDDI developed The PDDI interface was developed in connection with the ICAM project which was funded by the Air Force in order to improve the manufacturing methods in

Find the maximum shear stress at free end, Find the maximum shear stress at...

Find the maximum shear stress at free end: A stepped shaft ABCD, with A is fixed end and D is free end. AB = 1 m, BC = 2 m, CD = 1 m. AB is a hollow shaft of 100 mm outer diam

Principle of superposition, Principle of superposition: Explain the p...

Principle of superposition: Explain the principle of superposition. Sol.: A machine member is subjected to number of forces acting on its outer edges and also at some

Stroke -engine terminology , Stroke: The nominal distance through which a...

Stroke: The nominal distance through which a working piston moves between two successive reversals of its direction of motion is called the stroke and is designated by the letter

What is coating thickness, Q. What is Coating Thickness? The dry thickn...

Q. What is Coating Thickness? The dry thickness of the coating shall be checked by using a "micro test" magnetic gauge or approved equal which has been properly calibrated, at

Cold service insulation on pipe, Q. Cold service insulation on pipe? Fa...

Q. Cold service insulation on pipe? Factory fabricated sectional pipe insulation shall be applied in staggered joint construction. On multiple layer construction, all joints sh

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd