Electromagnetic conversion device with example., Mechanical Engineering

Assignment Help:

Q. In every electromagnetic conversion device, both generator and motor action take place simultaneously. Explain.

The case the output is mechanical as in a motoring mode, the coupling field must react with the electrical system as to absorb electrical energy from electrical system. In such a case i.e. in a motoring mode this reaction is counter emf e , similar to the emf induced in the primary winding of a transformer the coupling field extracts energy proportional to ei from the electrical system, converts it into mechanical from and delivers energy proportional to T? to the mechanical system.

In case the output is electrical as in a generating mode, the coupling field must react with mechanical system so as to absorb mechanical energy from mechanical system. In such a case ei, in a generating mode, this reaction is the counter torque T developed due to interactions of current i and the coupling field. Thus coupling field extracts mechanical energy proportional to T? from the mechanical system converts into electrical form and delivers energy proportional to ei to the electrical system.

Example

A coil with an axial length of 25 cm and diameter of 20 cm has 200 turns. It is placed in a uniform radial flux of 0.002 web/m2/ (a) If the coil is rotated at 25 rev. per sec., find the voltage induced in the coil. (b) What will be the force on each conductor and torque acting on the coil, if it carries a current of 10 Amps.

 l = 25 cm

 

            d = 20 cm

 

            N = 200 turn

 

            Φ = 0.002 ?b/m2

 

            V = 25 rev. per sec.

 

             e = T

 

             e = Blv

 

            B =  Φ/a

 

             a = π/4 (d2) = π/4 × (20 × 10-2)2 = 0.0314 m2

 

            B = 0.002/0.0314 T

 

            B = 0.06269 T

 

             e = 0.06363 × (25 × 10-2) × 25

 

             e = 0.398

 

             e = 0.4 volts

 

             f = BIl

 

            F = 0.06369 × 10 × 25 × 10-2 = 0.159225 newtons

 

            T = 2 IBRl

 

 

               = 2 × 10 × 0.06369 × 20/2 × 10-2 × 25 × 10-2 = 0.031845 N-m


Related Discussions:- Electromagnetic conversion device with example.

Belts, laws of belts ?

laws of belts ?

Explain about post-weld heat treatment, Q. Explain about Post-weld Heat Tre...

Q. Explain about Post-weld Heat Treatment? Post-weld Heat Treatment (PWHT) shall be in accordance with the Code. PWHT procedures, including properly identified charts or certi

Clutch free play-clutch complaints, Clutch free play : Check for free play ...

Clutch free play : Check for free play of the clutch lever. It should be within 10-20 mm.

Formula to make a parallelogram a rectangle, I need a formula to calculate ...

I need a formula to calculate the offset that would give me

What is ifc in project management, Q. What is IFC in project management? ...

Q. What is IFC in project management? This revision is to be used as a basis for preparing detailed design for final checking of IFC drawings by other disciplines, for incorpo

Determine the angular acceleration of the motion, Determine the angular acc...

Determine the angular acceleration of the motion: A flywheel of mass 15 kg and radius 20 cm is wound by a rope that carries a weight A of mass 5 kg at its free end as illustra

Vitrification-manufacturing methods of ceramics, Vitrification This is...

Vitrification This is liquid phase sintering. It is achieved via incorporating a component that melts to viscous liquid during sintering. Such viscous liquid solidifies in gla

Comparison between work and heat - thermodynamics, Comparison between work ...

Comparison between work and heat - thermodynamics: There are a number of similarities between heat and work. 1. Both heat and work are transient phenomena. The systems do n

Indicator diagram and indicated power - thermodynamics, Indicator diagram a...

Indicator diagram and indicated power: An indicated diagram is graph between pressure and volume. The former being taken on the vertical axis and latter on the horizontal axis

Determine mean coil radius - close coiled helical spring, Determine Mean co...

Determine Mean coil radius - close coiled helical spring:  A close coiled helical spring contains a stiffness of 1 kN/m in compression to a maximum load of 50 N and a maximum

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd