Electromagnetic conversion device with example., Mechanical Engineering

Assignment Help:

Q. In every electromagnetic conversion device, both generator and motor action take place simultaneously. Explain.

The case the output is mechanical as in a motoring mode, the coupling field must react with the electrical system as to absorb electrical energy from electrical system. In such a case i.e. in a motoring mode this reaction is counter emf e , similar to the emf induced in the primary winding of a transformer the coupling field extracts energy proportional to ei from the electrical system, converts it into mechanical from and delivers energy proportional to T? to the mechanical system.

In case the output is electrical as in a generating mode, the coupling field must react with mechanical system so as to absorb mechanical energy from mechanical system. In such a case ei, in a generating mode, this reaction is the counter torque T developed due to interactions of current i and the coupling field. Thus coupling field extracts mechanical energy proportional to T? from the mechanical system converts into electrical form and delivers energy proportional to ei to the electrical system.

Example

A coil with an axial length of 25 cm and diameter of 20 cm has 200 turns. It is placed in a uniform radial flux of 0.002 web/m2/ (a) If the coil is rotated at 25 rev. per sec., find the voltage induced in the coil. (b) What will be the force on each conductor and torque acting on the coil, if it carries a current of 10 Amps.

 l = 25 cm

 

            d = 20 cm

 

            N = 200 turn

 

            Φ = 0.002 ?b/m2

 

            V = 25 rev. per sec.

 

             e = T

 

             e = Blv

 

            B =  Φ/a

 

             a = π/4 (d2) = π/4 × (20 × 10-2)2 = 0.0314 m2

 

            B = 0.002/0.0314 T

 

            B = 0.06269 T

 

             e = 0.06363 × (25 × 10-2) × 25

 

             e = 0.398

 

             e = 0.4 volts

 

             f = BIl

 

            F = 0.06369 × 10 × 25 × 10-2 = 0.159225 newtons

 

            T = 2 IBRl

 

 

               = 2 × 10 × 0.06369 × 20/2 × 10-2 × 25 × 10-2 = 0.031845 N-m


Related Discussions:- Electromagnetic conversion device with example.

Projection welding, Projection Welding Projection welding is similar to...

Projection Welding Projection welding is similar to spot welding but for the fact that the welding takes place at the projections on the surface of the metals and flat shaped e

Evaluate boiler efficiency, The following data were obtained in a boiler tr...

The following data were obtained in a boiler trail: Mass and temperature of feed water: 680 kg/hr and 20 0 C, Steam temperature and its pressure : 15bar and 300 0 C, Coal used

Pressure and temperature in unfired pressure vessels, Q. Pressure and Tempe...

Q. Pressure and Temperature in Unfired pressure vessels? The design pressures and coincident maximum and minimum metal temperature, shall be determined by carefully considering

Principal stress and strain, The end gear is subjected to the loading given...

The end gear is subjected to the loading given in the picture below. If the bearings A & B exerts only Z & Y component of forces on the shaft, Verify the equilibrium torque T at ge

Piping stress analysis, The Mechanical Engineer/Specialist shall be respons...

The Mechanical Engineer/Specialist shall be responsible for coordinating project issues related to stress analysis, as they relate to his/her equipment, with the Stress Engineer/Sp

Explosive welding i cladding, EXPLOSIVE WELDING I CLADDING In this pr...

EXPLOSIVE WELDING I CLADDING In this process, two pieces of metal are impacted together at an extremely high velocity of impact achieved by the detonation of an explosive cha

Find out the product of inertia of a rectangular area, Find out the product...

Find out the product of inertia of a rectangular area: Find out the product of inertia of a rectangular area b × d with respect to its sides as illustrated in Figure Solut

Applications of spot welding, Applications of spot welding As spot weld...

Applications of spot welding As spot welding can be employed for Al, Cu, Ni and Mg alloys. It is not advisable to spot weld steels with carbon content greater than 0.25 % unles

Governor, where expendable pattern is used?

where expendable pattern is used?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd