Electromagnetic conversion device with example., Mechanical Engineering

Assignment Help:

Q. In every electromagnetic conversion device, both generator and motor action take place simultaneously. Explain.

The case the output is mechanical as in a motoring mode, the coupling field must react with the electrical system as to absorb electrical energy from electrical system. In such a case i.e. in a motoring mode this reaction is counter emf e , similar to the emf induced in the primary winding of a transformer the coupling field extracts energy proportional to ei from the electrical system, converts it into mechanical from and delivers energy proportional to T? to the mechanical system.

In case the output is electrical as in a generating mode, the coupling field must react with mechanical system so as to absorb mechanical energy from mechanical system. In such a case ei, in a generating mode, this reaction is the counter torque T developed due to interactions of current i and the coupling field. Thus coupling field extracts mechanical energy proportional to T? from the mechanical system converts into electrical form and delivers energy proportional to ei to the electrical system.

Example

A coil with an axial length of 25 cm and diameter of 20 cm has 200 turns. It is placed in a uniform radial flux of 0.002 web/m2/ (a) If the coil is rotated at 25 rev. per sec., find the voltage induced in the coil. (b) What will be the force on each conductor and torque acting on the coil, if it carries a current of 10 Amps.

 l = 25 cm

 

            d = 20 cm

 

            N = 200 turn

 

            Φ = 0.002 ?b/m2

 

            V = 25 rev. per sec.

 

             e = T

 

             e = Blv

 

            B =  Φ/a

 

             a = π/4 (d2) = π/4 × (20 × 10-2)2 = 0.0314 m2

 

            B = 0.002/0.0314 T

 

            B = 0.06269 T

 

             e = 0.06363 × (25 × 10-2) × 25

 

             e = 0.398

 

             e = 0.4 volts

 

             f = BIl

 

            F = 0.06369 × 10 × 25 × 10-2 = 0.159225 newtons

 

            T = 2 IBRl

 

 

               = 2 × 10 × 0.06369 × 20/2 × 10-2 × 25 × 10-2 = 0.031845 N-m


Related Discussions:- Electromagnetic conversion device with example.

Determine reactions at supports of loaded beam, Determine reactions at supp...

Determine reactions at supports of loaded beam: Determine reactions at supports A and B of loaded beam as shown in the figure given below.     Sol.: First co

Fluid Mechanics, temperature lapse rate differentiation integration...

temperature lapse rate differentiation integration...

Homogeneous and isotropic material, Homogeneous and isotropic material: ...

Homogeneous and isotropic material: A homogeneous material implies that elastic properties like modulus of elasticity and Poisson's ratio of material are same everywhere in

Calculate the significant figure, Do not round intermediate calculations, h...

Do not round intermediate calculations, however for display purposes report intermediate steps rounded to four significant figures. Give your final answer(s) to three significant f

Torsion , in the torsion equation the term j/r is called

in the torsion equation the term j/r is called

Cylinder head-basic components of engine , Cylinder Head: It is fitted at...

Cylinder Head: It is fitted at top of the cylinder block. It provides space for the arrangement of spark plug, combustion chamber, camshaft, cam chain, valves and intake and exha

Evaluate the motion of the system, Evaluate the motion of the system: ...

Evaluate the motion of the system: If in above Example, the block A is resting on an inclined plane at 45 o to horizontal as illustrative in Figure, find out the motion of th

Illustrate the types of special foundations, Illustrate the Types of specia...

Illustrate the Types of special foundations Special foundations find use under following situation: i)  To meet the demands that are arising from uncommon environmental cond

Thermophyics, The steam that leaves the super-heater is expanded from 130ba...

The steam that leaves the super-heater is expanded from 130bar at 535°C to 25.2bar at 310°C in a high pressure turbine. The steam from the exit of the HP turbine is reheated to 535

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd