Compute the total capacitance with parallel connection, Electrical Engineering

Compute the total capacitance with parallel connection:

Three capacitors C1, C2 and C3 contain capacitance 20 μf, 15 μf, 30 μf, respectively. compute:

1. Charge on each of the capacitor when connected in parallel with 220 V supply.

2. Total capacitance with parallel connection.

3. Voltage across each of the capacitor when connected in series and 220 V supply is given to this series connection.

Solution

 (a) Capacitors are in parallel:

2228_Compute the total capacitance with parallel connection.png

Figure

Q1 = C1 V = 20 × 10-6  × 220 = 4400 × 10

Q2 = C2 V = 15 × 10- 6 × 220 = 3300 × 10- 6 C

Q3  = C3 V = 30 × 10- 6 × 220 = 6600 × 10- 6  C

 (b)       Total capacitance :

      C = C1 + C2 + C3

          = (20 + 15 + 30) × 10- 6

           = 65 μF

(c) As capacitors are in series so charge Q remains same for all capacitors.

 

1365_Compute the total capacitance with parallel connection1.png

Figure

1 /Ceq      =  (1 / C1 )+   (1 / C2 ) +(1/C3)

1 / Ceq =   1 /20  + 1/15 + 1/30  = 0.05 + 0.0666 + 0.0333

 Ceq = 6.667 μF

Total charge Q = Ceq × V

= 1466.74 μC

Now,    Voltage across C1 is V1 = Q/ C1 = 73.337 volt

Voltage across C  is V   =  Q/ C2 == 97.78 volt

Voltage across C  is V  =  Q/C3  == 48.89 volt

Posted Date: 2/4/2013 5:18:08 AM | Location : United States







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