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Compute the magnitude and direction of the force:
Problem:
Compute the magnitude and direction of the force
F¯ = (320 N) i¯ + (450 N) j¯ - (600 N) k¯
Solution
The magnitude of the force F is specified by
= 815.41N
cos θx = Fx / F = 320 /815.41 = 0.3924
∴ θ x = 66o 53′ 36′
cos θ y = Fy/ F
= 450 / 815.41
= 0.5519
∴ θ y = 56o 30′ 16′
cos θz = Fz /F = - 600 / 815.41 = - 0.7358
∴ θz = 137o 22′ 29′′
Therefore, the force of 815.41 N is making an angle of 66o 53′ 36′′ along with x axis, 56o 30′ 16′′ along y axis and 137o 22′ with z axis.
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