## Complex numbers, Mathematics

Assignment Help:
How t determine locus of a goven point

#### Proof of: limq -0 sinq/q = 1 trig limits, Proof of: lim q →0 sin q...

Proof of: lim q →0 sin q / q = 1 This proofs of given limit uses the Squeeze Theorem. Though, getting things set up to utilize the Squeeze Theorem can be a somewha

#### Find an example of congruential unit random number generator, 1. Suppose th...

1. Suppose the arrival times of phone calls in a help centre follow a Poisson process with rate 20 per hour (so the inter-arrival times are independent exponential random variables

3+5

1/2+3/4

#### Describe simplifying fractions with example, Describe Simplifying Fractions...

Describe Simplifying Fractions with example? When a fraction cannot be reduced any further, the fraction is in its simplest form. To reduce a fraction to its simplest form, div

#### Commercial, The C.P. of 20 articles is same as theS.P. of x articles.Articl...

The C.P. of 20 articles is same as theS.P. of x articles.Article profit is 25%.Find x

#### Find the length of the parallelogram, The perimeter of a parallelogram is 5...

The perimeter of a parallelogram is 50 cm. The length of the parallelogram is 5 cm more than the width. Find the length of the parallelogram. Let w = the width of the parallelo

#### Boundary value problem, solve the in-homogenous problem where A and b are c...

solve the in-homogenous problem where A and b are constants on 0 ut=uxx+A exp(-bx) u(x,0)=A/b^2(1-exp(-bx)) u(0,t)=0 u(1,t)=-A/b^2 exp(-b)

#### Relation between hieght, volume=(1/3)(pi)(radius of base)2(height) curved ...

volume=(1/3)(pi)(radius of base)2(height) curved surface area=(pi)(r)(l), r is radius of base and l is length of straight line connecting apex of cone with point on edge of base

#### Taylor series - series solutions to differential equations, Once we get out...

Once we get out of the review, we are not going to be doing a lot with Taylor series, but they are a fine method to get us back into the swing of dealing with power series. Through  