Binary search tree, Data Structure & Algorithms

Assignment Help:

Objectives

The purpose of this project is to give you significant exposure to Binary Search Trees (BST), tree traversals, and recursive code.

Background

An arbitrary BST is seldom balanced. The left and right subtrees of a node may have different heights or contain different numbers of nodes, potentially leading to O( N ) performance for operations such as insert, find, and remove. There are several techniques for improving performance and insuring O( lg N ) performance by "balancing" the tree. Some of these will be discussed in class.

Description

In this project, you will explore balancing BST based on the weights of its subtrees. Here we define the weight of a BST to be the number of nodes in that tree. A node in a BST is weight-balanced if the weights of its left and right subtrees differ by no more than 1. A weight-balanced BST is a BST in which every node is weight-balanced. An important property of weight-balanced BST is that the value at any node, X, is a median of the values at all nodes in the subtree rooted at X.

How You're Program Works

Your program is invoked with two command line arguments. The first argument is the name of a file of integers (separated by whitespace) to read and insert into your BST. The second argument is the level to which your BSTs should be printed. Recall that the root is at level zero. For example

unix> ant run -Dargs="integers.dat 4"

Your program performs the following steps

  • Read the integers found in the file specified on the command line and insert them into an initially empty BST, let's call it T, ignoring duplicates.
  • Print the number of integers read from the file (including duplicates).
  • Print the number of nodes in T, the height and median value of T and then print the contents of T in level-order up to the level specified on the command line.
  • Weight-balance T according to the (admittedly inefficient) algorithm below.

    Weight Balance tree T

       find the median of T

       create a new BST, T', with a single node (the root) whose value is the median of T

       retrieve and insert elements of all nodes of T except the median into T'.

       replace T with T'           // T' has a weight-balanced root

       call this procedure to balance the left and right subtrees of T

Print the number of nodes in the weight-balanced tree, the height and median of the weight-balance tree and the contents of the tree in level-order up to the level specified on the command line.

Your Tasks

Design and implement a BST tree class which supports the required operations for this project. You are free to write your own BST from scratch or use some or all of the author's code as a starting point.

Project Requirements, Notes and Hints

    (R) Level-order printing

If the tree's height is less than the specified number of levels to print, then print the entire tree.

Tree nodes must be printed as ordered triples of values in the format ( x, y, z ), where x is the value found in the node's parent (print -1 for the root's parent), y is the value found in the node being printed and z is the weight of the tree rooted at that node.

Your level-order tree print must start with a label on a new line for each level, and print 4 nodes per line if there are more than 4 nodes at a given level.

The format for printing trees is shown in the sample output below.

(N) A level-order traversal requires use of a queue. Elements in the queue should contain appropriate data to print the required information.

(N) You are free to use any classes provided by the Java 6 API.

(N) The median of a set of values is the value "in the middle". If there are an even number of values, then there are two values "in the middle". In this project you should use the smaller of the two as the median.

(N) The algorithm given to weight-balance the tree is not the only possible algorithm, but we ask you to use this one so that your project output matches ours.

(H) Test your code with small files first, using non-random data then move to larger, more complex files.

(H) Some methods are better implemented as recursive functions, others as iterative functions. Choose your implementation carefully.

(H) By convention and for ease of coding, define the height of an empty tree as -1.

(H) Consider adding a new data member to each node which is the weight of the tree rooted at that node. The weight will make it easier to find the median and must be printed with each node. New nodes start with weight = 1. Nodes visited while finding the insertion point for a new node have their weight incremented if the integer being inserted is not a duplicate.

(H) Use the weight in the tree nodes described above to help find the median value. The median may be found with either a recursive or iterative algorithm.


Related Discussions:- Binary search tree

State the ruby programming language, The Ruby Programming Language Alth...

The Ruby Programming Language Although data structures and algorithms we study aren't tied to any program or programming language, we need to write particular programs in speci

Binary search tree, Objectives The purpose of this project is to give yo...

Objectives The purpose of this project is to give you significant exposure to Binary Search Trees (BST), tree traversals, and recursive code. Background An arbitrary BST i

Traversing a binary search tree, Binary Search Tree let three types of trav...

Binary Search Tree let three types of traversals by its nodes. They are: Pre Order Traversal In Order Traversal Post Order Traversal In Pre Order Traversal, we ca

Write an algorithm to display this repeated calculation, The following form...

The following formula is used to calculate n: n = x * x/(1 - x) . Value x = 0 is used to stop algorithm. Calculation is repeated using values of x until value x = 0 is input. There

Explain about the doubly linked list with neat diagram, Problem 1. Expl...

Problem 1. Explain about the doubly linked list with neat diagram. Diagram Explaining doubly linked list 2. Explain what are the criteria to be used in evaluatin

Drawback of sequential file, Following are some of the drawback of sequenti...

Following are some of the drawback of sequential file organisation: Updates are not simply accommodated. By definition, random access is impossible. All records should be

Binary tree creation, Binary tree creation struct NODE { struct N...

Binary tree creation struct NODE { struct NODE *left; int value; struct NODE *right; }; create_tree( struct NODE *curr, struct NODE *new ) { if(new->val

Addressing modes, Compare zero-address, one-address, two-address, and three...

Compare zero-address, one-address, two-address, and three-address machines by writing programs to compute: Y = (A – B X C) / (D + E X F) for each of the four machines. The inst

Enumerate about the carrier set members, Enumerate about the carrier set me...

Enumerate about the carrier set members Ruby is written in C, so carrier set members (which is, individual symbols) are implemented as fixed-size arrays of characters (which is

Explain about the abstract data type, Explain about the Abstract data type ...

Explain about the Abstract data type Abstract data type (ADT) A set of values (the carrier set) and operations on those values

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd