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Assume a complete binary tree T with n nodes where each node has an item (value). Label the nodes of the complete binary tree T from top to bottom & from left to right 0, 1, ..., n-1. Relate with T the array A where the ith entry of A is the item in the node labeled i of T, i = 0, 1, ..., n-1. Table illustrates the array representation of a Binary tree of Figure
Given the index i of a node, we can efficiently & easily compute the index of its parent and left & right children:
Index of Parent: (i - 1)/2, Index of Left Child: 2i + 1, Index of Right Child: 2i + 2.
Node #
Item
Left child
Right child
0
A
1
2
B
3
4
C
-1
D
5
6
E
7
8
G
H
I
J
9
?
Table: Array Representation of a Binary Tree
First column illustrates index of node, second column contain the item stored into the node & third & fourth columns mention the positions of left & right children
(-1 shows that there is no child to that specific node.)
Using the cohen sutherland. Algorithm. Find the visible portion of the line P(40,80) Q(120,30) inside the window is defined as ABCD A(20,20),B(60,20),C(60,40)and D(20,40)
Sorting is significant application activity. Several sorting algorithms are obtainable. But, each is efficient for a specific situation or a specific kind of data. The choice of a
bst for 40,60,25,50,30,70,35,10,55,65,12
Q. Write down an algorithm to sort a given list by making use of Quick sort method. Describe the behaviour of Quick sort when input given to us is already sorted.
Program will demonstrate deletion of an element from the linear array /* declaration of delete_list function */ voiddelete_list(list *, int); /* definition of delete_list
Polynomials like 5x 4 + 2x 3 + 7x 2 + 10x - 8 can be represented by using arrays. Arithmetic operations such as addition & multiplication of polynomials are com
What are the conditions under which sequential search of a list is preferred over binary search? Sequential Search is a preferred over binary search when the list is unordered
* Initialise d & pi* for each vertex v within V( g ) g.d[v] := infinity g.pi[v] := nil g.d[s] := 0; * Set S to empty * S := { 0 } Q := V(g) * While (V-S)
prove that n/100=omega(n)
You are given two jugs, a 4-gallon one and a 3-gallon one. Neither has any measuring marker on it. There is a tap that can be used to fill the jugs with water. How can you get exac
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