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Assume a complete binary tree T with n nodes where each node has an item (value). Label the nodes of the complete binary tree T from top to bottom & from left to right 0, 1, ..., n-1. Relate with T the array A where the ith entry of A is the item in the node labeled i of T, i = 0, 1, ..., n-1. Table illustrates the array representation of a Binary tree of Figure
Given the index i of a node, we can efficiently & easily compute the index of its parent and left & right children:
Index of Parent: (i - 1)/2, Index of Left Child: 2i + 1, Index of Right Child: 2i + 2.
Node #
Item
Left child
Right child
0
A
1
2
B
3
4
C
-1
D
5
6
E
7
8
G
H
I
J
9
?
Table: Array Representation of a Binary Tree
First column illustrates index of node, second column contain the item stored into the node & third & fourth columns mention the positions of left & right children
(-1 shows that there is no child to that specific node.)
What is the time complexity of Merge sort and Heap sort algorithms? Time complexity of merge sort is O(N log2 N) Time complexity of heap sort is O(nlog2n)
Demonstration of Polynomial using Linked List # include # include Struct link { Char sign; intcoef; int expo; struct link *next; }; Typedefstruct link
Which data structure is used for implementing recursion Stack.
Preorder traversal of a binary tree struct NODE { struct NODE *left; int value; /* can take any data type */ struct NODE *right; }; preorder(struct N
In this respect depth-first search (DFS) is the exact reverse process: whenever it sends a new node, it immediately continues to extend from it. It sends back to previously explore
difference between recursion and iteration
Q. Describe the representations of graph. Represent the graph which is given to us using any two methods Ans: The different ways by which we can represent graphs are:
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Q. Execute your algorithm to convert the infix expression to the post fix expression with the given infix expression as input Q = [(A + B)/(C + D) ↑ (E / F)]+ (G + H)/ I
Insertion & deletion of target key requires splaying of the tree. In case of insertion, the tree is splayed to find the target. If, target key is found out, then we have a duplicat
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