y² = t² - 3 is the actual implicit solution to y'= t/y, y(2) = -1. At such point I will ask that you trust me that it is actually a solution to the differential equation. You will learn how to acquire this solution in a later section.  The point of this illustration is that as there is a y² on the left side in place of a single y (t) this is not an explicit solution!

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