2(sin 6+cos6) - 3(sin4+cos4)+1 = 0, Mathematics

2(sin 6?+cos6?) - 3(sin4?+cos4?)+1 = 0

Ans:    (Sin2?)3  + (Cos2?)3-3 (Sin4?+(Cos4?)+1=0

Consider (Sin2?)3  +(Cos2?)3

⇒(Sin2?+Cos2?)3-3 Sin2?Cos2?( Sin2?+Cos2?)

= 1- 3Sin2? Cos2?

Sin4?+Cos4?(Sin2?)2+(Cos2?)2

= (Sin2?+Cos2?)2-2 Sin2? Cos2?

= 1- 2 Sin2? Cos2?

= 2(Sin6?+Cos6?)-3(Sin4?+Cos4?) +1

= 2 (1-3 Sin2? Cos2?)-3 (1-2 Sin2?+Cos2?)+1

 

Posted Date: 4/9/2013 1:51:53 AM | Location : United States







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