Convert to mips the following expression

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Reference no: EM13698834

The subsequent problems deal with translating from C to MIPS. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3, and $s4, respectively. Suppose that the base address of the arrays A and B are in registers $s6 and $s7, respectively.

Convert to MIPS the subsequent expression.

B[8] = A[i-j]

I have the answer already but i do not understand it; I need expert to guide through it step by step. thanks!

Reference no: EM13698834

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