C++ program that accepts 10 values of gallons

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Reference no: EM131399071

(cin within a loop) Write and run a C++ program that accepts 10 values of gallons, one at a time, and converts each value entered to its liter equivalent before the next value is requested. Use a for loop in your program. Use the fact that 1 gallon = 3.785 liters.

Reference no: EM131399071

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