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Write down the algorithm of quick sort. An algorithm for quick sort: void quicksort ( int a[ ], int lower, int upper ) { int i ; if ( upper > lower ) { i = split ( a, lower, upper ) ; quicksort ( a, lower, i - 1 ) ; quicksort ( a, i + 1, upper ) ; } } int split ( int a[ ], int lower, int upper ){ int i, p, q, t ;
p = lower + 1 ; q = upper ; i = a[lower] ; while ( q >= p ) { while ( a[p] < i ) p++ ; while ( a[q] > i ) q-- ; if ( q > p ) { t = a[p] ; a[p] = a[q] ; a[q] = t ; } } t = a[lower] ; a[lower] = a[q] ; a[q] = t ; return q ; }
Q. Explain the technique to calculate the address of an element in an array. A 25 × 4 matrix array DATA is stored in memory in 'row-major order'. If base address is 200 and
Explain what are circular queues? Write down routines required for inserting and deleting elements from a circular queue implemented using arrays. Circular queue:
For a queue a physical analogy is a line at booking counter. At booking counter, customers go to the rear (end) of the line & customers are attended to several services from the fr
How to measure the algorithm's efficiency? It is logical to examine the algorithm's efficiency as a function of some parameter n showing the algorithm's input size. Instance
Write the algorithm for compound interest
Explain class P problems Class P is a class of decision problems that can be solved in polynomial time by(deterministic) algorithms. This class of problems is kno
Q.1 Write procedures/ Algorithm to insert and delete an element in to array. Q.2. Write an algorithm for binary search. What are the conditions under which sequential search of
Let us assume a sparse matrix from storage view point. Assume that the entire sparse matrix is stored. Then, a significant amount of memory that stores the matrix consists of zeroe
N = number of rows of the graph D[i[j] = C[i][j] For k from 1 to n Do for i = 1 to n Do for j = 1 to n D[i[j]= minimum( d ij (k-1) ,d ik (k-1) +d kj (k-1)
Asymptotic notation Let us describe a few functions in terms of above asymptotic notation. Example: f(n) = 3n 3 + 2n 2 + 4n + 3 = 3n 3 + 2n 2 + O (n), as 4n + 3 is of
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