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A: void displayBits( unsigned value )
{
const int SHIFT = 8 * sizeof( unsigned ) - 1;
const unsigned MASK = 1<< SHIFT;
cout << setw(10 ) << value << " = ";
for ( unsigned i = 1; i <= SHIFT + 1; i++ )
cout << ( value & MASK ? '1' : '0' );
value <<= 1;
if ( i % 8 == 0 ) // output a space after bits cout << ' ';
}
cout << endl;
You may do the same by divide by 2, till the number is greator than 0. However you ought to use stack to print it in reverse order.
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want a c code soon
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pseudo code that will determine if the number is prime or composite
A Padovan string P(n) for a natural number n is defined as: P(0) = ‘X’ P(1) = ‘Y’ P(2) = ‘Z’ P(n) = P(n-2) + P(n-3), n>2 where + denotes string concatenation. For a string of t
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