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Q. Why is it complicated to protect a system in which users are allowed to do their own I/O?
Answer: In earlier chapters we identified a distinction among kernel and user mode where kernel mode is utilized for carrying out privileged operations such as I/O. One reason why I/O should be performed in kernel mode is that I/O requires accessing the hardware as well as proper access to the hardware is necessary for system integrity. If we permit users to perform their own I/O we can't guarantee system integrity.
One reason to learn C and C++ is simply that so much software is written in these languages. A related, butmore fundamental reason, is that C and C++ are relatively low-level, allo
#question After working for 30 years, Ramjee Somjee Dutt opted for VRS and started a courier company and did very well in the first four years. He was now looking for expansion of
Explain the basic concepts of segmentation. Segmentation definition User view of program Hardware used with diagram-segment table, base, limit & offset Protection and
Problem: Managing Outside Communication. a. What is the principal action we use when communicating through a web browser? b. Give an example of how to preaddress an email
What is a Real-time system? A Real-time system is used when inflexible time requirements have placed on the operation of processor or the flow of data so it is often used as a
PART A Question 1 Using your own words, explain what a continuous random variable and a continuous probability density function are. Give examples. Question 2 Gi
why we say OS is a resource allocator and control program
What are the necessary conditions for deadlocks? 1. Mutual exclusion : Only one process at a time is able to use the resource. 2. Hold and wait : A process should be holdi
1. What must a kernel provide for an effective user-level thread implementation? 2. With respect to the quantum q in a scheduling algorithm, explain and discuss the impact of the
Q. Consider a file at present consisting of 100 blocks. Presume that the file control block (and the index block in the case of indexed allocation) is already in memory. Compute h
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