White''s general heteroscedasticity test, Advanced Statistics

Assignment Help:

The Null Hypothesis - H0:  γ1 = γ2 = ...  =  0  i.e.  there is no heteroscedasticity in the model

The Alternative Hypothesis - H1:  at least one of the γi's are not equal to zero i.e. the squared residuals are related to one of the independent variables.

Reject H0 if nR2   >   2094_Tests for Heteroscedasticity.png

Regression Analysis: sqresi versus totexp, age, ...

* sqnk is highly correlated with other X variables

* sqnk has been removed from the equation.

 

The regression equation is

sqresi = 0.00086 - 0.000117 totexp + 0.000765 age + 0.00007 nk

         + 0.000000 sqtotexp - 0.000009 sqage + 0.000000 totexpage

         + 0.000026 totexpnk - 0.000077 agenk

 

Predictor         Coef     SE Coef      T      P     VIF

Constant      0.000857    0.007288   0.12  0.906

totexp     -0.00011676  0.00004906  -2.38  0.017  49.148

age          0.0007649   0.0003256   2.35  0.019  73.466

nk            0.000072    0.002941   0.02  0.980  24.250

sqtotexp    0.00000019  0.00000010   2.00  0.045  13.958

sqage      -0.00000879  0.00000394  -2.23  0.026  62.515

totexpage   0.00000021  0.00000097   0.21  0.831  37.830

totexpnk    0.00002598  0.00001464   1.77  0.076  18.920

agenk      -0.00007694  0.00007905  -0.97  0.331  32.566

S = 0.0112807   R-Sq = 1.2%   R-Sq(adj) = 0.6%

 

Analysis of Variance

Source            DF         SS         MS     F      P

Regression         8  0.0022313  0.0002789  2.19  0.026

Residual Error  1493  0.1899897  0.0001273

  Lack of Fit    639  0.0804237  0.0001259  0.98  0.601

  Pure Error     854  0.1095659  0.0001283

Total           1501  0.1922209

 

 332 rows with no replicates

Source     DF     Seq SS

totexp      1  0.0006642

age         1  0.0000000

nk          1  0.0000026

sqtotexp    1  0.0005240

sqage       1  0.0005895

totexpage   1  0.0000013

totexpnk    1  0.0003292

agenk       1  0.0001206

 

MTB > let k4=1502*0.012

MTB > print k4

Data Display

K4    18.0240

Inverse Cumulative Distribution Function

Chi-Square with 8 DF

P( X <= x )        x

       0.95  15.5073

Since nrsq = (1502*0.012) 18.024 > 15.5073 = 2094_Tests for Heteroscedasticity.png, there is sufficient evidence to reject H0 which suggests that there is heteroscedasticity in the model from White's general heteroscedasticity test at the 5% significance level.  Both Breusch Pagan test and White's general heteroscedasticity test seem to indicate that totexp is the culprit as the T value is significant and the P-value is 0.000.


Related Discussions:- White''s general heteroscedasticity test

Mixture experiment, Mixture experiment is an experiment in which the two o...

Mixture experiment is an experiment in which the two or more ingredients are blended together to form an end product. The measurements are taken on the several blends of the ingre

Network sampling, Network sampling is a sampling design in which the simpl...

Network sampling is a sampling design in which the simple random sample or strati?ed sample of the sampling units is made and all observational units which are linked to any of th

Explanatory variables, The variables appearing on the right-hand side of eq...

The variables appearing on the right-hand side of equations defining, for instance, multiple regressions or the logistic regression, and which seek to predict or 'explain' response

Linear Programming, 1. The production manager of Koulder Refrigerators must...

1. The production manager of Koulder Refrigerators must decide how many refrigerators to produce in each of the next four months to meet demand at the lowest overall cost. There i

Define matching coefficient, Matching coefficient is a similarity coeffici...

Matching coefficient is a similarity coefficient for data consisting of the number of binary variables which is often used in cluster analysis. It can be given as follows    he

What is the expectation of the number of tosses required, Question 1 A box...

Question 1 A box contains 20 fuses of which 5 are defective If 2 fuses are chosen together at random what is the probability that both the fuses are defective? Question 2 A c

Random allocation, Random allocation is a technique for creating the treat...

Random allocation is a technique for creating the treatment and control groups particularly in accordance of the clinical trial. Subjects receive the active treatment or the place

Linearity - reasons for screening data, Linearity - Reasons for Screening D...

Linearity - Reasons for Screening Data Many of the technics of standard statistical analysis are based on the assumption that the relationship, if any, between variables is li

Blinder oaxaca method, Blinder Oaxaca method: A method or technique used f...

Blinder Oaxaca method: A method or technique used for assessing the effect of the role of income on racial wealth gap. The method or technique is based on the decomposition of the

Odds ratio, Odds ratio is the ratio of the odds for the binary variable in...

Odds ratio is the ratio of the odds for the binary variable in two groups of the subjects, such as, males and females. If the two possible states of variable are labeled as 'succe

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd