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A: Mostly can be overloaded. The only C operators which can't be are. and?: (and sizeof, that is technically an operator). C++ adds a few of its own operators, mostly which can be overloaded except :: and .*.
Here's an instance of the subscript operator (it returns a reference). Primary without operator overloading:
class Array {
public:
int& elem(unsigned i) { if (i > 99) error(); return data[i]; }
private:
int data[100];
};
int main()
{
Array a; a.elem(10) = 42; a.elem(12) += a.elem(13);
...
}
Now the similar logic is presented along with operator overloading:
int& operator[] (unsigned i) { if (i > 99) error(); return data[i]; }
Array a; a[10] = 42; a[12] += a[13];
#quGiven the Array class definition in Fig. 11.10-11.11 (pp. 476-479) of the textbook, write a new overloaded operator function for the ‘%’ (modulus) operator (i.e., return an arra
How are postfix and prefix versions of operator++ () differentiated? A: The postfix version of operator++ () contain a dummy parameter of type int. The prefix version does not c
decoding message
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Explain each of the algorithms in a way that would be understandable to an intelligent person who is not familiar with programming. You should not use any code (or even pseudo code
describe user manuals?
Is there any difficulty with the following : char*a=NULL; char& p = *a;? A: The result is indeterminate. You must never do this. A reference has to always refer to some object.
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write a c program chat illustrates the creation of child process using fork system call. One process finds sum of even series and other process finds sum of odd series.
Using Figure 10.2 as a model, illustrate the result of each operation in the sequence ENQUEUE.Q; 4/, ENQUEUE.Q; 1/, ENQUEUE.Q; 3/, DEQUEUE.Q/, ENQUEUE.Q; 8/, and DEQUEUE.Q/ on an i
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