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What is internal fragmentation?
Consider holes of 20k assume the process requests 18 bites. If we allocate accurately the request block, we are left with a hole of 2k. The overhead to keep follow of the hole will be considerably larger than the Hole itself. The common approach is to break the main memory in units of block size as with this approach the allocated memory to a process may be slightly larger than he requested memory. The dissimilarity between these two numbers is internal fragmentation (memory internal to a process but cannot be used).
Q. Why page sizes always powers of 2? Answer: Recall that paging is executed by breaking up an address into a page and offset number. It is most competent to break the address
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Pure and impure interpreters In a pure interpreter, the source program is maintained in the source form throughout its interpretation. This arrangement acquires substantia
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We have stressed the need for an operating system to make efficient use of the computing hardware. When is it appropriate for the operating system to forsake this principle and to
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How File record length should be chosen File record length should be selected to match the data characteristics
Hashed page table method A general approach for managing address spaces larger than 32 bits is to use a hashed page table with the hash values being the virtual-page number.
Define the “Throughput” of a system Throughput is Number of programs processed by it per unit time
Explain about demand paging? A demand paging system is same to a paging system with swapping. Processes reside on secondary memory. When we require executing a process, we chan
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