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Deriving the Solution from the Model: This phase is devoted to the computation of those value of decision variables that maximize or minimize the objective function. Such solution is called an optimal solution.
Validity of the Model: The model should be validated to measure its accuracy . that is in order for a model to be useful, the degree to which it actually represents the systems or problem being modelled must be established. A models valid or accurate if.
a. It contains all the objective constraints and decision variables relevant to the problem.
b. The objectives constraints and decision variable included in the model are all relevant to or actually part of the problem and
c. The functional relationship are valid.
A FIRM MANUFACTURES HAEDACHE PILLS IN TWO SIZE A AND B
#A paper mill produces two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper
3. A paper mill produces two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y pape
The following linear programming is written to plan the production of two products. And the company wants to maximize profits. x1 = number of product 1 produced in each batch
SOLVE THE FOLLOWING LP USING SIMPLE METHOD MAXIMIZE Z=3X1+2X2 SUBJECT TO CONSTRAINT X1+X2 X1-X2 X1,X2>=0
A paper mill produces two grades of paper viz., X and Y. Because of raw material restrictions, it cannot produce more than 400 tons of grade X paper and 300 tons of grade Y paper i
Important to Theoretical Distribution The science of theoretical distribution under which the frequencies of a variable are derived by some mathematical model without
#Solve the following Linear Programming Problem using Simplex method. Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 = 4 X1 - X2 = 2 X1, X2 = 0
Solve the following Linear Programming Problem using Simple method. Maximize Z= 3x1 + 2X2 Subject to the constraints: X1+ X2 = 4 X1 - X2 = 2 X1, X2 = 0
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