Write a program to find the area under the curve y =, Other Engineering

Assignment Help:

#questiWrite a program to find the area under the curve y = f(x) between x = a and x = b, integrate y = f(x) between the limits of a and b. The area under a curve between two points can be found by doing a definite integral between the two points.
on..

 

Solution

#include
float    start_point,            /* GLOBAL VARIABLES */

    end_point,
    total_area;
int    numtraps;
main( )
{
   void    input(void);
   float    find_area(float a,float b,int n); /* prototype */


   print(“AREA UNDER A CURVE”);
   input( );
   total_area = find_area(start_point, end_point, numtraps);
   printf(“TOTAL AREA = %f”, total_area);
}
void input(void)
{
   printf(“\n Enter lower limit:”);
   scanf(“%f”, &start_point);
   printf(“Enter upper limit:”);
   scanf(“%f”, &end_point);
   printf(“Enter number of trapezoids:”);
   scanf(“%d”, &numtraps);
}
float find_area(float a, float b, int n)
{
      floatbase, lower, h1, h2;    /* LOCAL VARIABLES */
float function_x(float x);    /* prototype */
float trap_area(float h1,float h2,floatbase);/*prototype*/
base = (b-1)/n;
         lower = a;
       for(lower =a; lower <= b-base; lower = lower + base)
    {
    h1  =  function_x(lower);
             h1  =  function_x(lower + base);
             total_area += trap_area(h1, h2, base);
    }
return(total_area);
    float trap_area(float height_1,float height_2,floatbase)
        {
       float area;    /* LOCAL VARIABLE */

       area = 0.5 * (height_1 + height_2) * base;
         return(area);
    }
    float function_x(float x)
    {
         /* F(X) = X * X + 1 */
return(x*x + 1);
    }
   
Output

    AREA UNDER A CURVE
    Enter lower limit: 0
    Enter upper limit:  3
    Enter number of trapezoids: 30
    TOTAL AREA   =  12.005000

    AREA UNDER A CURVE
    Enter lower limit: 0
    Enter upper limit: 3
    Enter number of trapezoids: 100
    TOTAL AREA = 12.000438


Related Discussions:- Write a program to find the area under the curve y =

4 bit comparator, process / description.. if I put A=1000 and B=0100 A>B ga...

process / description.. if I put A=1000 and B=0100 A>B gate will show output 1 and dose A

Synchro resolvers for low load, Synchro resolvers for low load: Both tr...

Synchro resolvers for low load: Both transmitter and receiver rotors are energised by the same AC supply and will induce equal and opposing voltages in the stator coils provide

Thrust augmentation - aircraft engine , Thrust augmentation: There are ...

Thrust augmentation: There are occasions when the maximum thrust from a basic gas turbine engine is inadequate and some method of increasing the available thrust is required wi

Petroleum Production.., 1. . Using the graph of pore/fracture pressure for ...

1. . Using the graph of pore/fracture pressure for the Holly Field propose a casing scheme for the well using the graphical approach. Discuss the suitability of the selected casing

System architecture and design, The home work is to make an model based sys...

The home work is to make an model based system architecture for an electrical car. in Enterprise Architecture with SysMl language.

Cascaded, circit diagram and operation

circit diagram and operation

Unit operations , Can you guys Solve Unit Operations Problems in Chemical e...

Can you guys Solve Unit Operations Problems in Chemical engineering

What are the elements limiting higher data rate in networks, Question: ...

Question: (a) What are the elements limiting high data rate in cellular networks? (b) Describe the following characteristics of 4G mobile networks: - Always on - RAN A

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd