Thermal properties-ceramics-refractory and abrasive material, Mechanical Engineering

Assignment Help:

Thermal Properties

Each solid expand on heating and convention on cooling. The thermal expansion of solids is due to basic structure whether atoms occupy mean position on a fixed distance from each other. In actual fact atoms are not stationary but vibrate about mean location or positions which changes along with temperature. The distance in between mean positions rises along with increasing temperature and reduces along with temperature. Such changes in the mean distance in between the atoms result in contraction or expansion. Coefficient of linear expansion is explained as the raise in length per till length per degree rise in temperature. For reduces in temperature similar property is regarded as -ive . The linear changes in three mutually perpendicular directions will constitute volume expansion coefficient. If the linear expansion coefficients in three orthogonal directions are equivalent then the solid is thermally isotropic. The thermal expansion is zero on absolute zero temperature and is usually related to exact heat and melting point of a substance.

This is interesting to notice that experiments express that total volume change on heating among absolute zero and melting point is same for each element. This implies that thermal expansion coefficient is low for high melting point solids. Most solids that are utilized for high temperature applications that are refractory materials have linearly varying thermal coefficients. The exception is silica as SiO2 and zirconia ZrO2 which due to polymorphic transformation implies irregular behaviour.

The coefficient of thermal expansion is significant consideration though designing structure to operate at high temperature. The limited deformations will reason forces to act upon the part and hence induce stresses. Further throughout moulding procedure proper care require to be exercised for volume's due consideration and linear changes after solidification hence dimensional accuracy and tolerances might be maintained. Apparently this consideration supposes greater significance in case of such materials that are not easy to machine. Ceramics and further refractory materials are illustrations.

                                   1809_Thermal properties.png

Figure: Thermal Expansion of Refractory Oxides as Function of Temperature

The coefficient of plastics of expansion might be controlled by addition of filler material; usually increasing filler material would reduce the coefficient. Expansion in instance of reinforced plastics tends to arise in the direction of reinforcement. There are a lot of plastics utilized in conjunction along with metals of common employ and it might be noted that employ of fillers enable material engineer to control the coefficient such plastic and metal expand equally. Unequal expansion will initiate undesirable deformation and stresses.


Related Discussions:- Thermal properties-ceramics-refractory and abrasive material

Newton''s second and third law of motion, Newton's second and  third law o...

Newton's second and  third law of motion: Newton's second law of motion: If resultant force is acting on particle is not zero, and then acceleration of particle will be prop

Polythionic Acid Stress Corrosion Cracking, In Naphtha Hydrotreating Unit, ...

In Naphtha Hydrotreating Unit, does feed/effluent heat exchangers require passivation to avoid polythionic acid stress corrosion cracking.

Chemical and physical delay, Illustrate the process of knock in C.I engines...

Illustrate the process of knock in C.I engines and compare it with S.I. engine knock. What is Octane rating of C.I. engine fuel. What is the difference between chemical delay and p

Machine and tool selection , Machine and Tool Selection The quality of...

Machine and Tool Selection The quality of a product largely depends on the type of machine, the type of process, machining conditions and the right selection of tools. The cur

Calculate the radius of plates, Calculate the radius of plates: A lami...

Calculate the radius of plates: A laminated steel spring, simply supported at the ends & centrally loaded, along a span of 0.8 m; is needed to carry a proof load of 8 kN; and

Briefly explain how geothermal powerplant operate, Illustrate types of nucl...

Illustrate types of nuclear reactors with diagrams? a) Give advantages and disadvantages of nuclear power plant? b) Briefly explain how geothermal powerplant operate with fig

What is fusion bonding, Q. What is Fusion Bonding? Fusion Bonding shall...

Q. What is Fusion Bonding? Fusion Bonding shall refer to the fusion bond coating process which utilizes heat to melt adhere the coating material to the metal surface. Fusion Bo

Results for the underlying problem-conventional priority , Results for the ...

Results for the Underlying Problem The rules mentioned above and several variants of these rules that became out to be inferior are tested for eight various conditions of the

Drag link mechanism, why there is a different angular velocity in the two c...

why there is a different angular velocity in the two cranks of a drag link mechanism?

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd