The tic-tac-toe program, JAVA Programming

Assignment Help:

Instructions

Modify the program so that the computer will generate moves for the
‘O' player (it must continue to accept user input for ‘X'). A simple way to do this is to use a random value between 0 and 9 to generate moves for ‘O'.

currMove = (int)(Math.random() * 9) + 1;

You will have to ensure, of course, that the computer does not generate a move for a square that is already occupied. Another simple way to generate moves is to simply move to the first unoccupied square.

Also I need explain in words (as clearly and precisely as possible) any improvements you made to the program.

Any other improvement to make this program looks better please sent me in a different attach.

The Program

/**
* Homework Assignment #1 -- Working With Two-Dimensional Arrays (Tic-Tac-Toe)
* CPS , Section [[Put your section number here]]
*
* @author [[Put your name here]]
* @version 1.1 [[Put current date here]]
*/
import java.util.Scanner;

public class Hmwk1 {

public static final char SPACE = ' ';
// Tic-tac-toe board showing move numbers
public static final char[][] MOVE_INFO = {{'1', '2', '3'},
{'4', '5', '6'},
{'7', '8', '9'}};

public static void main(String[] args) {
Scanner in = new Scanner(System.in);

char[][] board = new char[3][3];
char currPlayer = 'X';

fill2D(board, SPACE);
printBoard(MOVE_INFO);
while (!gameOver(board)) {
System.err.print("Move for " + currPlayer + "? ");
int currMove = in.nextInt();
makeMove(currPlayer, currMove, board);
printBoard(board);
currPlayer = nextPlayer(currPlayer);
}
reportResults(board);
}

/**
* Fill a given two-dimensional character array with a given
* character
*
* @param a the array to fill
* @param c the character to use
*/
public static void fill2D(char[][] a, char c) {
for (int i = 0; i < a.length; i++) {
for (int j = 0; j < a[i].length; j++) {
a[i][j] = c;
}
}
}

public static final String VERT = " * * ";
public static final String HORZ = "***********";

/**
* Print the contents of an array representing a tic-tac-toe
* board
*
* @param board the board configuration to be printed
*/
public static void printBoard(char[][] board) {
System.out.println();
for (int i = 0; i < board.length; i++) {
System.out.println(VERT);
for (int j = 0; j < board[i].length; j++) {
System.out.print(" " + board[i][j] + " ");
if (j < board[i].length - 1) {
System.out.print("*");
} else {
System.out.println();
}
}
System.out.println(VERT);
if (i < board.length - 1) {
System.out.println(HORZ);
}
}
System.out.println();
}

/**
* Determine if the game is over; i.e., if a player has won or if
* there are no more moves possible
*
* @param board current board configuration
* @return true if game is over, false otherwise
*/
public static boolean gameOver(char[][] board) {
return noMovesLeft(board)
|| isWinner('X', board)
|| isWinner('O', board);
}

/**
* Determine if no more moves are possible; i.e., if there
* are no more SPACE's left in the board array
*
* @param board the current board configuration
* @return true if there are no more legal moves, false otherwise
*/
public static boolean noMovesLeft(char[][] board) {
for (int i = 0; i < board.length; i++) {
for (int j = 0; j < board[i].length; j++) {
if (board[i][j] == SPACE) {
return false;
}
}
}
return true;
}

/**
* Determine if a given player is a winner; i.e., has 3 marks in a
* row, either horizontally, vertically, or diagonally
*
* @param player the player to check
* @param board the current board configuration
* @return true if player has 3 marks in a row, false otherwise
*/
public static boolean isWinner(char player, char[][] board) {
// check rows (horizontal)
for (int row = 0; row < 3; row++) {
if (board[row][0] == player && board[row][1] == player
&& board[row][2] == player) {
return true;
}
}
// check cols (vertical)
for (int col = 0; col < 3; col++) {
if (board[0][col] == player && board[1][col] == player
&& board[2][col] == player) {
return true;
}
}
// check diagonals
if (board[0][0] == player && board[1][1] == player
&& board[2][2] == player) {
return true;
} else if (board[0][2] == player && board[1][1] == player
&& board[2][0] == player) {
return true;
} else {
return false;
}
}

/**
* Mark the specified move for the specified player on the given
* board configuration (move == 1 => [0][0], move == 2 => [0][1],
* move == 3 => [0][2], move == 4 => [1][0], move == 5 => [1][1],
* move == 6 => [1][2], move == 7 => [2][0], move == 8 => [2][1],
* move == 9 => [2][2])
*
* @param player the player making the move
* @param move the move to be made
* @param board the current board configuration
*/
public static void makeMove(char player, int move, char[][] board) {
int row = (move - 1) / board.length;
int col = (move - 1) % board[row].length;
board[row][col] = player;
}

/**
* Determine the next player, for cycling X, then O, then X, etc.
*
* @param current the current player ('X' or 'O')
* @return the next player to play ('O' or 'X')
*/
public static char nextPlayer(char current) {
if (current == 'X') {
return 'O';
} else {
return 'X';
}
}

/**
* Report the results of the game, whether X or O won or the game
* ended in a tie.
*
* @param board the board configuration to be described
*/
public static void reportResults(char[][] board) {
if (isWinner('O', board)) {
System.out.println("O is the winner!");
} else if (isWinner('X', board)) {
System.out.println("X is the winner!");
} else {
System.out.println("The game ends in a tie.");
}
}

}


Related Discussions:- The tic-tac-toe program

Java web services, #quThis project is based on the teams example of chapter...

#quThis project is based on the teams example of chapter 1. Instead of teams, you will consider employees working in a department in a company. (Departments and employees are ana

Bluej program, program to find the frequency of a digit in a number

program to find the frequency of a digit in a number

Need facebook developer, Project Description: i am seeking an experience...

Project Description: i am seeking an experienced Facebook page builder,fanpage builder, Header module Navigation menu module HTML module Widget module Image modul

Develop news feed android app design template, Project Description: You ...

Project Description: You should give A Working, Sample Android .apk Project and Java source code Original Photoshop PSD that I can edit and customize to fit my needs All S

Define object-to-relational (o/r) mapping, Object-to-Relational (O/R) mappi...

Object-to-Relational (O/R) mapping : There are various ways to persist data and the persistence layer is one of the most important layers in any application development. O/R ma

Explain the uses of JVM verifier, Explain the uses of JVM verifier The ...

Explain the uses of JVM verifier The JVM "verifier" checks the code when it's loaded to verify that it has the correct structure --that it does not use an uninitialized pointer

Difference b/w deep cloning and shallow cloning of object, The default natu...

The default nature of an object's clone() function automatically provides a shallow copy. So to need a deep copy the classes have to be edited or adjusted.   Shallow co

Write Your Message!

Captcha
Free Assignment Quote

Assured A++ Grade

Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!

All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd