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Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 86 feet.
a) Set up an equation for the perimeter involving only L, the length of the rectangle. b) Solve this linear equation algebraically to find the length of the rectangle. Find the width as well. c) Using the same width from your answer on part b), find a new perimeter when the new length is five less than three times the width.
In figure, the incircle of triangle ABC touches the sides BC, CA, and AB at D, E, and F respectively. Show that AF+BD+CE=AE+BF+CD= 1/2 (perimeter of triangle ABC), Ans:
solve for x: logx9
uses of maths concept
Three quantities a, b and c are said to be in harmonic progression if, In this case we observe that we have to consider three terms in o
Equation for the given intervaks in the intervaks, giving ypout answer correct to 0.1 1.sin x = 0.8 0 2. cos x =-0.3 -180 3.4cos theta- cos theta=2 0 4. 10tan theta+3=0 0
IN THIS WE HAVE TO ADD THE PROBABILITY of 3 and 5 occuring separtely and subtract prob. of 3 and 5 occuring together therefore p=(166+100-33)/500=233/500=0.466
Find out the area of the region enclosed by y = x 2 & y =√x . Solution Firstly, just what do we mean by "area enclosed by". This means that the region we're interested in
Equations of Planes Earlier we saw a couple of equations of planes. Though, none of those equations had three variables in them and were actually extensions of graphs which we
(2a+8b)
draw a equilateral triangle with length of side 6.5 cm. and let us draw a parallelogram equal in area to that triangle and having an angle 45 degree
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