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Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 86 feet.
a) Set up an equation for the perimeter involving only L, the length of the rectangle. b) Solve this linear equation algebraically to find the length of the rectangle. Find the width as well. c) Using the same width from your answer on part b), find a new perimeter when the new length is five less than three times the width.
importance of lp
The actual solution is the specific solution to a differential equation which not only satisfies the differential equation, although also satisfies the specified initial conditions
Computation method Whereas L = Lower class boundary of the class having the mode f 0 = Frequency of the class below the modal class
2.46825141458*1456814314.446825558556
how can i round decimals
Geometric Applications to the Cross Product There are a so many geometric applications to the cross product also. Assume we have three vectors a → , b → and c → and we make
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1.)3 3/8 divided by 4 7/8 plus 3 2.)4 1/2 minus 3/4 divided by 2 3/8
The Fourier series expansion for the periodic function, f ( t ) = |sin t | is defined in its fundamental interval. Taking π = 3.142, calculate the Fourier cosine series app
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