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Suppose that the width of a rectangle is three feet shorter than length and that the perimeter of the rectangle is 86 feet.
a) Set up an equation for the perimeter involving only L, the length of the rectangle. b) Solve this linear equation algebraically to find the length of the rectangle. Find the width as well. c) Using the same width from your answer on part b), find a new perimeter when the new length is five less than three times the width.
a painting is 20 cm wider than its height. its area is 2400 centimeter squared. find its lenght and width
In the figure, ABCD is a square inside a circle with centre O. The Centre of the square coincides with O & the diagonal AC is horizontal of AP, DQ are vertical & AP = 45 cm, DQ = 2
The general solution to a differential equation is the most common form which the solution can take and does not take any initial conditions in account. Illustration 5: y(t) =
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Will has a bag of gumdrops. If he eats 2 of his gumdrops, he will have among 2 and 6 of them left. Which of the subsequent represents how many gumdrops, x, were originally in his b
I had just come back from a very interesting talk arranged by a Mathematics Centre, it was aimed at parents of primary school-going children. They had talked about, and demonstrate
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1.)3 3/8 divided by 4 7/8 plus 3 2.)4 1/2 minus 3/4 divided by 2 3/8
1+3+5+7+9+11+13+15+17+19
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