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1 gm of a metallic oxide on reduction gives 0.68 gm of the metal.
ans) Mass of metal/mass of oxygen=eq. mass of metal/eq. mass of oxygen.applying this we get.68/.32=x/8x=17 gm
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Which of the following is always a whole number : (1) Atomic weight (2) Atomic radii (3) Equivalent weight (4) Atomic number Ans: Atomic number
500-600 words
molecular chlorine and molecular fluorine combine to form a gaseous product.Under the same conditions of temperature and pressure it is found that one volume of Cl2 reacts with thr
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