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The electronic configuration of four elements are given in brackets:
L (1s2, 2s2, 2p1, ) M (1s1, 2s2, 2p5)
Q (1s2, 2s2, 2p6 3s1,) R ( 1s1, 2s2, 2p2)
The element that would most readily form a diatomic molecule is:
(1) Q
(2) M
(3) R
(4) L
Ans: M
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Prove that the number of orbitals in a principal quantum level is n^2 using the fact that the number of orbitals in a subshell is (2L-1) where L is the azimuthal quantum number.
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