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The electronic configuration of four elements are given in brackets:
L (1s2, 2s2, 2p1, ) M (1s1, 2s2, 2p5)
Q (1s2, 2s2, 2p6 3s1,) R ( 1s1, 2s2, 2p2)
The element that would most readily form a diatomic molecule is:
(1) Q
(2) M
(3) R
(4) L
Ans: M
No. of valence orbitals- No of Hybrid orbitals.Apply the formula for no. of hybrid orbitals.If it exceeds 4 then the answer is 0.
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Explain Solubility of one liquid in another -Liquid–Liquid Equilibria Suppose substances A and B are both liquids when pure. In discussing the solubility of liquid B in li
Which of the following compound has electrovalent linkage: (1) CH 3 Cl (2) Nacl (3) CH 4
How does it help in stabilising a structure Ans) More alpha hydrogens more hyper conjugations More hyper conjugation more is the stability Less inductive effect more hyper
what is the actanoid contraction
writethe sort farmula of learn the pariodik table.
The elements of this group form a number of compounds with halogens. The halogen compounds of S. Se, Te and Po are called as halides. For oxygen, only the fluoro compounds
libermann nitroso reaction
Derive Nerst equation for both anode and cathode.
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