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Solve out following inequalities. Give both inequality & interval notation forms for the solution.
-14 < -7 (3x + 2) < 1
Solution
-14< -21x -14 < 1
0 < -21x < 15
Don't get excited regarding the fact that one of the sides is zero now. It isn't a problem. Again, as with the last part, we'll be dividing through a negative number and thus don't forget to switch the direction of the inequalities.
0 > x> -15 /21
0 > x> 5/7 OR - 5/7 The interval notation of the solution is ( -5/7,0)
The interval notation of the solution is ( -5/7,0)
There is a third method that we'll be looking at to solve systems of two equations, but it's a little more complicated and is probably more useful for systems with at least three e
-1/5t>7 -
solve x-y=8 and x+y=4 using one of the algebraic methods
(3x+2y+2z) + (3x+5y+3z)
As noted earlier most parabolas are not given in that form. So, we have to take a look at how to graph a parabola which is in the general form.
y=mx+b for x
Consider the function y = 2x. the domain is restricted to 0 = x = 4, what is the range of this function
w^2 + 30w + 81= (-9x^3 + 3x^2 - 15x)/(-3x) (14y = 8y^2 + y^3 + 12)/(6 + y) ac + xc + aw^2 + xw^2 10a^2- 27ab + 5b^2 For the last problem I have to incorporate the following words
can you explain to me how to solve x^3+x+5
v(5)
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