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Solve for unknowns 'x' and 'y' from Equations (1) and (2) using MATLAB. (However, if MATLAB is not the appropriate software to solve these two simultaneous equations, please suggest other methods, thanks!)
Equation (1)
0.5*exp(y*-29)+2.175/x*exp(y*-27)+4.47/x*exp(y*-26)+1.659/x*exp(y*-24)+1.76/x*exp(y*-21)+4.26/x*exp(y*-20)+11/x*exp(y*-19)+4.02/x*exp(y*-18)+4.44/x*exp(y*-17)+4.44/x*exp(y*-14)+10.36/x*exp(y*-13)+3.713/x*exp(y*-12)+1.33/x*exp(y*-11)+2.175/x*exp(y*-9)+2.556/x*exp(y*-6)+10.36/x*exp(y*-5)+3.375/x*exp(y*-4) = 1.3671
Equation (2)
0.5*exp(y*-58)+2.175/x*exp(y*-56)+4.47/x*exp(y*-55)+1.659/x*exp(y*-53)+1.76/x*exp(y*-50)+4.26/x*exp(y*-49)+11/x*exp(y*-48)+4.02/x*exp(y*-47)+4.44/x*exp(y*-46)+4.44/x*exp(y*-43)+10.36/x*exp(y*-42)+3.713/x*exp(y*-41)+1.33/x*exp(y*-40)+2.175/x*exp(y*-38)+2.556/x*exp(y*-35)+10.36/x*exp(y*-34)+3.375/x*exp(y*-33)+1.659/x*exp(y*-29)+4.44/x*exp(y*-28)+4.56/x*exp(y*-27)+2.175/x*exp(y*-26)+4.26/x*exp(y*-23)+1.76/x*exp(y*-20)+4.56/x*exp(y*-18)+11/x*exp(y*-16)+2.175/x*exp(y*-15)+3.2/x*exp(y*-14)+2.556/x*exp(y*-12)+3.713/x*exp(y*-9)+10.36/x*exp(y*-8)+10.36/x*exp(y*-6)+5.77/x*exp(y*-4) = 1.8642
whats thye procedure for entering say an LP model, maximisation an objective funtion ''10x+3y'' subject to: 40 300x +298y>=299 x+y=1
Type logical: The type logical is used to store the true/false values. If any variables have been formed in the Command Window, they can be seen at the Workspace Window. In
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Why Function stubs are used?
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