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Example 2
Max Z = 3x1 - x2
Subject to
2x1 + x2 ≥ 2
x1 + 3x2 ≤ 3
x2 ≤ 4
& x1 ≥ 0, x2 ≥ 0
Answer
SLPP
Max Z = 3x1 - x2 + 0s1 + 0s2 + 0s3 - M a1
2x1 + x2 - s1+ a1= 2
x1 + 3x2 + s2 = 3
x2 + s3 = 4
x1 , x2 , s1, s2, s3, a1 ≥ 0
As all Δj ≥ 0, optimal basic feasible solution is achieved. Hence the solution is Max Z = 9, x1 = 3, x2 = 0
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Example 2 Max Z = 3x 1 - x 2 Subject to 2x 1 + x 2 ≥ 2 x 1 + 3x 2 ≤ 3 x 2 ≤ 4 & x 1 ≥ 0, x 2 ≥ 0 A
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