Solution by quadratic formula, Mathematics

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Help me how to solve equation by Quadratic Formula.

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Arithmetic, 25/5(2+3)

25/5(2+3)

Jermy 2/12/2013 2:34:50 AM try this, it will help you in your assignment. Consider the common quadratic equation Ax² + bx + c = 0 whereas a ≠ 0 The roots of the equation are obtained via the given formula as: X = (-b + √(b² - 4ac))/2a Example Solve for x ia formula 5x² + 2x - 3 = 0 Solution a = 5 and b = 2 and c = - 3 X = (-b + √(b² - 4ac))/2a X = (-2 + √(2² - 4(5)(-3)))/2(5) X = 3/5 or -1

Jermy

2/12/2013 2:34:50 AM

try this, it will help you in your assignment.

Consider the common quadratic equation

Ax² + bx + c = 0 whereas a ≠ 0

The roots of the equation are obtained via the given formula as:

X = (-b + √(b² - 4ac))/2a

Example

Solve for x ia formula

5x² + 2x - 3 = 0

Solution

a = 5 and b = 2 and c = - 3

X = (-b + √(b² - 4ac))/2a

X = (-2 + √(2² - 4(5)(-3)))/2(5)

X = 3/5 or -1

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