shares and dividends, Mathematics

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Class 10, chapter permutation & combination ex :4.6

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In the introduction of this section we briefly talked how a system of differential equations can occur from a population problem wherein we remain track of the population of both t

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Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C.  Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0

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express the complex number z=5+i divide 2+3i in the form a+ib

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