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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
Obesity - Choose one macronutrient (carbohydrates) and one micronutrient (vitamins) that have some relationship to the disease. Conduct a brief web search to learn about the ro
Explain the Filiform papillae These are long and slender and are the smallest of the three types of papillae. They are found to be most numerous on the edges and anterior two t
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