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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
The Feudal Society: The economic basis of the feudal system was land, and the village was its economic unit. The feudal economy was dependent on local agricultural production
Define age related changes in Excretory System There is a progressive decrease in the number and size of nephrons fiasic unit of the kidney). There is a 10% decrease in renal p
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PROCEDURE 1. Assume that your Counsellor is the Head of the Institution. 2. Your Counsellor will choose three of you and form a Survey Committee as follows: one of yo
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Another way to show that air expands when heated Snap a toy balloon over the neck of a small bottle and place the bottle in a pan of warm water.
The Maximum theoretical limit of channel is governed by Nyquist theorem, which says Bth = 2 x freq in hertz x log2L ( where L = number of level) Thus we have in this case Bth= 2x60
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