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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
Explain the Aplastic Anaemia Bone marrow aplasia means 'lack of functioning of bone marrow'. This can occur due to excessive X-ray or radiation treatment, certain industrial ch
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Answer the following questions: (a) What are the objectives of the Bischoff PBPK model? What useful predictions is the model capable of making? How is the model able to transla
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