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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
Question 1: (a) Define the following terms: normal baseline, internal waters and territorial sea. (b) List four responsibilities of the coastal state within the territoria
TO SHOW THAT AIR HAS WEIGHT Drive a thin nail by the exact centre of a long rod such as a metre stick or a yard stick. Balance the stick by resting the nail on the rims of two
For water soluble/miscible solid and liquid wastes The familiar method of mopping the waste with plenty of water and running the same into the drainage could be done for miscib
how do the currents produced by a 1.5V flashlight cell and a 12 V car battery compare if the resistance is the same?
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