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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
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Nematodes These are next to protozoa and are the abundant soil microfauna in soil. They are also called eelworms, thread worms or roundworms. Nematodes that feed on decayin
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These are the case studies that will be used to partly assess your taught elements of Fine Chemical Production. There were lectures mainly dealing with the scale up of equipment th
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Describe the factors which decide the broad area of Scientific activity?
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Dietary Requirement during Fever and Infection: During fever, there is a break down of tissue proteins, and water and salts are lost. The BMR increases with the rise of ever
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