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We know from Shannon's Theorem,Maximum data rate of a channel in bps (B) = Hlog2 ( 1+S/N ) _ 1Where H = bandwidth in HzS/N = signal-to-noise ratioWe also know thatDb = 10log10 S/NWhere Db= signal-to-noise ratio in decibel (which is in this case 20)So20 = 10 log10 S/N2 = log10 S/NAnd we get S/N = 100Putting this value of S/N in equation 1 we getB = 6000 log2 (1+100) = 6000 x 6.6582= 39949.2 bps or 39.949 kbpsSo the maximum achievable data rate here is 39.949 kbps
Cellulose:- It is the main constituent of plant cell walls and the most common and abundant of the D-glucose polymers. This does not occur in the animal body. It is a homopoly
Explain the factors that influence Glomerular Filtration Rate These include: 1) Renal blood flow: A large proportion of blood flows into the glomerulus. The greater the rate
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#question: Describe the factors which decide the broad area of Scientific activity ?
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