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A representation of an array structure is a mapping of the (abstract) array with elements of type T onto the store which is an array with elements of type BYTE. The array could be mapped in such a way that the computation of addresses of array elements is as simple as possible. The address i of the j-th array elements is computed by the linear mapping function
i = i0 + j*s
where i is the address of the first element, and s is the number of words that a element occupies. Assuming that the word is the smallest personally transferable unit of store, it is evidently highly needed that s be a whole number value, the simplest case being s = 1. If s is not a whole number, then s is generally rounded up to the next larger integer S. Each array component then accepts S words, whereby S-s words are left unused. Rounding up of the number of words required to the next whole number is called padding. The storage utilization factor u is the quotient of the minimal amounts of storage required to represent a structure and of the value actually used:
If a node in a binary tree is not containing left or right child or it is a leaf node then that absence of child node can be represented by the null pointers. The space engaged by
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write an algorithm given each students name and grade points for six courses.find his grade point average and group students into the gpa groups 3.5
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Q. The degree of a node is defined as the number of children it has. Shear show that in any binary tree, the total number of leaves is one more than the number of nodes of degree 2
Illustrates the program segment for Quick sort. It uses recursion. Program 1: Quick Sort Quicksort(A,m,n) int A[ ],m,n { int i, j, k; if m { i=m; j=n+1; k
What are the conditions under which sequential search of a list is preferred over binary search? Sequential Search is a preferred over binary search when the list is unordered
Let G=(V,E) be a graph for which all nodes have degree 5 and where G is 5-edge is connected. a) Show that the vector x which is indexed by the edges E and for which xe = 1/5 for
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