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Find the remainder when 7^103 is divided by 24 Solution) we know by the concept of mod that..... 49 is congruent to 1 mod 24(means if 1 is subtracted fom 49 u get 48 which is divisible by 24) so 7^2congruent to 1 mod 24 so 7^102congruent to 1 mod 24(raising to the power 51) hence the remainder when 7^102 is divided by 24 is 1 i.e. 7^102=24m+1 so multipling by 7 both sides we have....7^103=24.7m+ 7hence 7^103=24n + 7so remainder is 7 (ans)
#question.
sin^2alpha *sec^2beta +tan^2 beta *cos^2alpha=sin^2alpha+tan^2 beta
$36.00*6/36+(-$3.60)x30/36
I've termed this section as Intervals of Validity since all of the illustrations will involve them. Though, there is many more to this section. We will notice a couple of theorems
x>4
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give me some examples on continuity
Four is added to the quantity two minus the sum of negative seven and six. This answer is then multiplied through three. What is the result? This problem translates to the expr
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