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Find the remainder when 7^103 is divided by 24 Solution) we know by the concept of mod that..... 49 is congruent to 1 mod 24(means if 1 is subtracted fom 49 u get 48 which is divisible by 24) so 7^2congruent to 1 mod 24 so 7^102congruent to 1 mod 24(raising to the power 51) hence the remainder when 7^102 is divided by 24 is 1 i.e. 7^102=24m+1 so multipling by 7 both sides we have....7^103=24.7m+ 7hence 7^103=24n + 7so remainder is 7 (ans)
2*9
trigonometric ratios of sum and difference of two angles
1. Write down the canonical equations of the line passing through the point A(2,3, 4) and being parallel to the vector q ={5,0,-1}.
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Evaluate the below given limit. Solution Note as well that we actually do have to do the right-hand limit here. We know that the natural logarithm is just described fo
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