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Find the remainder when 7^103 is divided by 24 Solution) we know by the concept of mod that..... 49 is congruent to 1 mod 24(means if 1 is subtracted fom 49 u get 48 which is divisible by 24) so 7^2congruent to 1 mod 24 so 7^102congruent to 1 mod 24(raising to the power 51) hence the remainder when 7^102 is divided by 24 is 1 i.e. 7^102=24m+1 so multipling by 7 both sides we have....7^103=24.7m+ 7hence 7^103=24n + 7so remainder is 7 (ans)
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Question: Use Gauss elimination method to solve the following system of equations. -y +3z=4 2x-y-2z= 2 2x-2y+z =6 4x-y-7z= 0
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Determine dy & Δy if y = cos ( x 2 + 1) - x as x changes from x = 2 to x = 2.03 . Solution Firstly let's deetrmine actual the change in y, Δy . Δy = cos (( 2.03) 2
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