relative motion, Mathematics

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how to find the minimum distance between any two particles which are in relative motion?

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integral 0 to pi e^cosx cos (sinx) dx, Let u = sin(x). Then du = cos(x) dx...

Let u = sin(x). Then du = cos(x) dx. So you can now antidifferentiate e^u du. This is e^u + C = e^sin(x) + C.  Then substitute your range 0 to pi. e^sin (pi)-e^sin(0) =0-0 =0

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If t2+t+1=0 , t=w,w 2 L.H.S (w+w 2 ) + (w 2 + w) 2 ........  1  + 1 ....

t=w,w 2 L.H.S (w+w 2 ) + (w 2 + w) 2 ........  1  + 1 ..... But every third term is of the form: (w 3n +w 3n ) 2 =22 There are nine such terms. Their sum is 36. The rema

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The HCF & LCM of two expressions are respectively (x+3) and (x cube-7x+6). If one is x square+2x-3 , other is? Solution) (x+3) * (x^3-7x+6) = (x^2+2x-3) * y      ( ) (HCF*LCM=

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