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There are three typical ways of recursively traversing a binary tree. In each of these, the left sub-trees & right sub-trees are visited recursively and the distinguishing feature is when the element in the root is visited or processed.
Program, Program3 and Program 4 illustrated the inorder, preorder and postorder traversals of a Binary tree.
Program : Inorder traversal of a binary tree
struct NODE *left;
int value; /* can take any data type */
struct NODE *right;
};
inorder(struct NODE *curr)
{
if(curr->left != NULL)
inorder(curr->left);
printf("%d", curr->value);
if(curr->right != NULL)
inorder(curr->right);
}
5. Implement a stack (write pseudo-code for STACK-EMPTY, PUSH, and POP) using a singly linked list L. The operations PUSH and POP should still take O(1) time.
Representation of Linked list in Memory:- Each node has an info part and a pointer to the next node also known as link. The number of pointers is two in case of doubly linked
Q. Construct a binary tree whose nodes in inorder and preorder are written as follows: Inorder : 10, 15, 17, 18, 20, 25, 30, 35, 38, 40, 50 Preorder: 20, 15, 10
A town contains a total of 5000 houses. Every house owner has to pay tax based on value of the house. Houses over $200 000 pay 2% of their value in tax, houses over $100 000 pay 1.
A binary search tree is used to locate the number 43. Which of the following probe sequences are possible and which are not? Explain. (a) 61 52 14 17 40 43 (b) 2 3 50 40 60 43 (c)
algorithm to search a node in linked list
Retrieval of information is made simpler when it is stored into some predefined order. Therefore, Sorting is a very important computer application activity. Several sorting algorit
The below figure illustrates the BOM (Bill of Materials) for product A. The MPS (Material requirements Planning) start row in the master production schedule for product A calls for
how do we use 4-discs stack to solve tower of hanoi problem and write an algorithm to solve it?
Write an algorithm for binary search. Algorithm for Binary Search 1. if (low> high) 2. return (-1) 3. Mid = (low + high)/2 4. if ( X = = a[mid]) 5. return (mid); 6.
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