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There are three typical ways of recursively traversing a binary tree. In each of these, the left sub-trees & right sub-trees are visited recursively and the distinguishing feature is when the element in the root is visited or processed.
Program, Program3 and Program 4 illustrated the inorder, preorder and postorder traversals of a Binary tree.
Program : Inorder traversal of a binary tree
struct NODE *left;
int value; /* can take any data type */
struct NODE *right;
};
inorder(struct NODE *curr)
{
if(curr->left != NULL)
inorder(curr->left);
printf("%d", curr->value);
if(curr->right != NULL)
inorder(curr->right);
}
Explain in brief about the Container An entity which holds finitely many other entities. Just as containers such as boxes, baskets, bags, pails, cans, drawers, and so for
Q. Explain that how do we implement two stacks in one array A[1..n] in such a way that neither the stack overflows unless the total number of elements in both stacks together is n.
Post order traversal: The children of node are visited before the node itself; the root is visited last. Each node is visited after its descendents are visited. Algorithm fo
Q. Draw a B-tree of order 3 for the sequence of keys written below: 2, 4, 9, 8, 7, 6, 3, 1, 5, 10
By changing the NULL lines in a binary tree to the special links called threads, it is possible to execute traversal, insertion and deletion without using either a stack or recursi
Example of worse case of time
What is A Container Taxonomy It's useful to place containers in a taxonomy to help understand their relationships to one another and as a basis for implementation using a class
Q. Construct a complete binary tree with depth 3 for this tree which is maintained in the memory using the linked representation. Make the adjacency list and adjacency matrix for t
Write a function that performs the integer mod function. Given the previous functions you have implemented already, this one should be a piece of cake. This function will find the
1. Start 2. Get h 3. If h T=288.15+(h*-0.0065) 4. else if h T=216.65 5. else if h T=216.65+(h*0.001) 6. else if h T=228.65+(h*0.0028) 7. else if h T=270.65 8.
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