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If the rational number x= b/ c is a zero of the nth degree polynomial,
P ( x ) = sxn+ ...........+ t
Where every the coefficients are integers then b will be a factor of t & c will be a factor of s.
Note that in order for this theorem to work then the zero have to be reduced to lowest terms. In other terms it will work for 4/3 but not necessarily for 20/15.
Now, let's get back to parabolas. There is a basic procedure we can always use to get a pretty good sketch of a parabola. Following it is. 1. Determine the vertex. We'll discus
Example : Solve (x+ 1 / x - 5 )≤ 0 . Solution Before we get into solving these we need to point out that these don't solve in the similar way which we've solve equations
the table shows the number of minutes of excirccise for each person compare and contrast the measures of variation for both weeks
1/4-12
x 8/9 + = 6
three ordered pair
What are all of the points of intersection for these two hyperbolas? Hyperbola 1 is centered at (-1, 829). Its foci are located at (-5.123, 829) and (3.123, 829). Everywhere along
if A is an ideal and phi is onto S,then phi(A)is an ideal.
if the square of a positive number is decreased by 10, the result is 6. find the number
-2
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