Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Explain that how do we implement two stacks in one array A[1..n] in such a way that neither the stack overflows unless the total number of elements in both stacks together is n. The PUSH and POP operations should be running in O(1) time.
Ans:
Two stacks s1 and s2 can be implemented in one array A[1,2,...,N] as shown in the following figure
1 2 3 4 n-3 n-2 n-1 n S1 S2 Here we define A[1] as the bottom of stack S1 and let S1 "grow" to the right and we define A[n] as the bottom of the stack S2 and S2 "grow" to the left. In this particular case, overflow will occur, only S1 and S2 together have more than n elements. This technique or method will usually decrease the number of times overflow occurs. There will be separate push1, push2, pop1 and pop2 functions which are to be defined separately for the two stacks S1 and S2.
1 2 3 4 n-3 n-2 n-1 n
S1 S2
Here we define A[1] as the bottom of stack S1 and let S1 "grow" to the right and we define A[n] as the bottom of the stack S2 and S2 "grow" to the left. In this particular case, overflow will occur, only S1 and S2 together have more than n elements. This technique or method will usually decrease the number of times overflow occurs. There will be separate push1, push2, pop1 and pop2 functions which are to be defined separately for the two stacks S1 and S2.
Chaining In this method, instead of hashing function value as location we use it as an index into an array of pointers. Every pointer access a chain that holds the element havi
for (i = 0; i sequence of statements } Here, the loop executes n times. Thus, the sequence of statements also executes n times. Since we suppose the time complexity of th
1. Start 2. Get h 3. If h T=288.15+(h*-0.0065) 4. else if h T=216.65 5. else if h T=216.65+(h*0.001) 6. else if h T=228.65+(h*0.0028) 7. else if h T=270.65 8.
prove that n/100=omega(n)
Thread By changing the NULL lines in a binary tree to special links known as threads, it is possible to perform traversal, insertion and deletion without using either a stack
Suppose you are given the results of 5 games of rock-paper-scissors. The results are given to you on separate pieces of paper; each piece says either 'A' if the first person won, o
The algorithm to delete any node having key from a binary search tree is not simple where as several cases has to be considered. If the node to be deleted contains no sons,
Example: Insertion of a key 33 into a B-Tree (w/split) Step 1: Search first node for key closet to 33. Key 30 was determined. Step 2: Node pointed through key 30, is se
In this part, students are allowed to implement the following simplifications in their table and data design. o Availability for the beauty therapists don't have to be considere
extra key inserted at end of array is called
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +1-415-670-9521
Phone: +1-415-670-9521
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd