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In figure, XP and XQ are tangents from X to the circle with centre O. R is a point on the circle. Prove that XA+AR=XB+BR
Ans: Since the length of tangents from external point to a circle are equal
XP = XQ PA = RA BQ = BR
XP = XQ
⇒XA + PA = XB + BQ
⇒XA + AR = XB + BR (Θ PA = AR & BQ = BR)
Hence proved
A lotus is 2m above the water in a pond. Due to wind the lotus slides on the side and only the stem completely submerges in the water at a distance of 10m from the original positio
Q. Sum and Difference Identities? Ans. These six sum and difference identities express trigonometric functions of (u ± v) as functions of u and v alone.
6 7/10+8 9/4
f(x)=sin x+cos x in the interval {0,90}
compare: 643,251: 633,512: 633,893. The answer is 633,512.
Lindy has 48 chocolate chip cookies and 64 vanilla wafer cookies. How many bags can Lindy fill if she puts the chocolate chip cookies and the vanilla wafers in the same bag? She pl
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i have a question about discret math
A boy standing on a horizontal plane finds a bird flying at a distance of 100m from him at an elevation of 300. A girl standing on the roof of 20 meter high building finds the angl
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