Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
ABCD is a rectangle. Δ ADE and Δ ABF are two triangles such that ∠E=∠F as shown in the figure. Prove that AD x AF=AE x AB.
Ans: Consider Δ ADE and Δ ABF
∠D = ∠B = 90o
∠E = ∠F (given)
∴Δ ADE ≅ Δ ABF
AD/AB = AE/AF
⇒ AD x AF = AB x AE Proved
castor brought 6 3/4 carat cakes to share with 26 students. did castor bring enough for each student to have 1/4 of cake?
what is the concept of lmc
Find out the product of 5.2 × 10 3 and 6.5 × 10 7 . Write your answer in scientific notation. To multiply numbers written within scienti?c notation, multiply the ?rst numbers
Explain how we Converting Fractions to Percents ? To convert a fraction to a percent: 1. Convert the fraction to a decimal using long division. 2. Move the decimal point two p
Define Cofactor of an Element.
Four is added to the quantity two minus the sum of negative seven and six. This answer is then multiplied through three. What is the result? This problem translates to the expr
The sum of the diameters of two circles is 2.8 m and their difference of circumferences is 0.88m. Find the radii of the two circles (Ans: 77, 63) Ans: d 1 + d 2 = 2.8 m=
Solve 2 ln (√x) - ln (1 - x ) = 2 . Solution: Firstly get the two logarithms combined in a single logarithm. 2 ln (√x) - ln (x - l) = 2 ln ((√x) 2 ) ln (1 - x ) = 2
Find interval for which the function f(x)=xe x(1-x) is increasing or decreasing function
Standardizing a Random Variable If X is a random variable with E(X) = m and V(X) = s 2 , then Y = (X – m)/ s is a random variable with mean 0 and standard deviatio
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd