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ABCD is a rectangle. Δ ADE and Δ ABF are two triangles such that ∠E=∠F as shown in the figure. Prove that AD x AF=AE x AB.
Ans: Consider Δ ADE and Δ ABF
∠D = ∠B = 90o
∠E = ∠F (given)
∴Δ ADE ≅ Δ ABF
AD/AB = AE/AF
⇒ AD x AF = AB x AE Proved
An irrigation system uses a straight 30m sprinkler pipe which is capped at one end and arranged so that all water is released directly downwards and pivots around a central point.
First, see that the right hand side of equation (2) is a polynomial and thus continuous. This implies that this can only change sign if this firstly goes by zero. Therefore, if the
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25/5(2+3)
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