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ABC is a right triangle right-angled at C and AC=√3 BC. Prove that ∠ABC=60o.
Ans: Tan B = AC/BC
Tan B = √3 BC/BC
Tan B =√3
⇒ Tan B = Tan 60
⇒ B = 60o
⇒ ∠ABC = 60o
Hence proved
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