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Prove that a simple graph is connected if and only if it has a spanning tree.
Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G. By the definition of a tree, there is a path among any two nodes of T. As T is a subgraph of G, there is a path among each pair of nodes in G. Hence G is connected.
Here now let G is connected. If G is a tree then nothing to prove. If G is not a tree, it must consist of a simple circuit. Let G has n nodes. We can choose (n - 1) arcs from G in such type of a way that they not form a circuit. It results into a subgraph comprising all nodes and only (n - 1) arcs. So by definition this subgraph is a spanning tree.
In parallelogram ABCD, ∠A = 5x + 2 and ∠C = 6x - 4. Find the evaluation of ∠A. a. 32° b. 6° c. 84.7° d. 44° a. Opposite angles of a parallelogram are same in measu
the sides of a quad taken at random are x+3y-7=0 x-2y-5=0 3x+2y-7=0 7x-y+17=0 obtain the equation of the diagonals
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The students of a class are made to stand in complete rows. If one student is more in each row, there would be 2 rows less, and if one student is less in every row, there would be
Find out the roots of the subsequent pure quadratic equation: Find out the roots of the subsequent pure quadratic equation. 4x 2 - 100 = 0 Solution: Using Equation
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Andy earned the subsequent grades on his four math quizzes: 97, 78, 84, and 86. What is the average of his four quiz grades? To ?nd out the average, you must add the items (97
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