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Prove that a simple graph is connected if and only if it has a spanning tree.
Ans: First assume that a simple graph G has a spanning tree T. T consists of every node of G. By the definition of a tree, there is a path among any two nodes of T. As T is a subgraph of G, there is a path among each pair of nodes in G. Hence G is connected.
Here now let G is connected. If G is a tree then nothing to prove. If G is not a tree, it must consist of a simple circuit. Let G has n nodes. We can choose (n - 1) arcs from G in such type of a way that they not form a circuit. It results into a subgraph comprising all nodes and only (n - 1) arcs. So by definition this subgraph is a spanning tree.
We'll include this section with the definition of the radical. If n is a +ve integer that is greater than one and a is a real number then, Where n is termed as the index,
Judgment Sampling Here the interviewer chooses whom to interview believing that their view is more fundamental because they might be directly affected for illustration, to find
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in the horizontal bar event the u.s.a scored 28.636,gremany scroed 28.7,romnia scored 27.962,and chain scored 28.537 points.which list shows these scored in descending order
round to the nearest hundreths 1677.76
If OA = OB = 14cm, ∠AOB=90 o , find the area of shaded region. (Ans:21cm 2 ) Ans: Area of the shaded region = Area of ? AOB - Area of Semi Circle = 1/2 x 14 x
im having trouble with this problem: 6tons 1500lb/5
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