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Properties of Logarithms
1. logb1 = 0 . It follows from the fact that bo = 1.
2. logb b = 1. It follows from the fact that b 1= b .
3. logb bx = x . it can be generalized out to blog b f ( x ) = f ( x ).
4. b logb x = x . It can be generalized out to b logb f ( x ) = f ( x ) .
Properties 3 and 4 lead to a pleasant relationship among the logarithm & exponential function.
Let's first calculate the following function compositions for f ( x )= b x and g ( x ) = logb x .
( f o g )( x ) = f [g ( x )] = f (logb x ) = b logb x = x
( g o f ) ( x ) = g [f ( x )]= g [b x ] = log b bx = x
Remember again from the section on inverse functions which this means that the exponential & logarithm functions are inverses of each other. It is a nice fact to remember on occasion.
We have to also give the generalized version of Properties 3 & 4 in terms of both the natural and common logarithm
ln e f ( x ) = f ( x) log10 f ( x ) = f ( x)
eln f ( x ) = f ( x ) 10log f ( x ) = f ( x )
so I''m having trouble. I honestly don''t under stand this. Y=4x+5. y=-1/4x+4 they want me to tell whether the line is parallel, perpendicular or neither I don''t know how.
2(5x-4)-6
how to change the number to letter
9x-2y=3
Exponential function As a last topic in this section we have to discuss a special exponential function. Actually this is so special that for several people it is THE exponenti
10000000004*56464684654654
#If the common factor is known how do you find what the entire equation be (ex: A varies directly with t^2; A=8 when t=2. What is the formula?)
9
let x,y,z be the complex number such that x+y+z=2,x^2+y^2+z^=3,x*y*z=4,then 1/(x*y+z-1)+1/(x*z+y-1)+1/(y*z+x-1) is
(81x^2/256)^1/4
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