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Properties of Logarithms
1. logb1 = 0 . It follows from the fact that bo = 1.
2. logb b = 1. It follows from the fact that b 1= b .
3. logb bx = x . it can be generalized out to blog b f ( x ) = f ( x ).
4. b logb x = x . It can be generalized out to b logb f ( x ) = f ( x ) .
Properties 3 and 4 lead to a pleasant relationship among the logarithm & exponential function.
Let's first calculate the following function compositions for f ( x )= b x and g ( x ) = logb x .
( f o g )( x ) = f [g ( x )] = f (logb x ) = b logb x = x
( g o f ) ( x ) = g [f ( x )]= g [b x ] = log b bx = x
Remember again from the section on inverse functions which this means that the exponential & logarithm functions are inverses of each other. It is a nice fact to remember on occasion.
We have to also give the generalized version of Properties 3 & 4 in terms of both the natural and common logarithm
ln e f ( x ) = f ( x) log10 f ( x ) = f ( x)
eln f ( x ) = f ( x ) 10log f ( x ) = f ( x )
how much is 101+200+
ue Week 7 and worth 55 points Five (5) years ago, you bought a house for $171,000, with a down payment of $30,000, which meant you took out a loan for $141,000. Your interest rate
4(x)^2-40x+107 in standard form
Example If 8 ×10 14 joules of energy is released at the time of an earthquake what was the magnitude of the earthquake? Solution There actually isn't much to do here o
w^2 + 30w + 81= (-9x^3 + 3x^2 - 15x)/(-3x) (14y = 8y^2 + y^3 + 12)/(6 + y) ac + xc + aw^2 + xw^2 10a^2- 27ab + 5b^2 For the last problem I have to incorporate the following words
Utilizes augmented matrices to solve out each of the following systems. x - y = 6 -2x + 2 y = 1 Solution Now, already we've worked this one out therefore we know that
If m
(2+x)+y=2+(x+y)
There are several quantities out there within the world which are governed (at least for a short time period) by the equation,
5(4a+1)+6=-(-11a+1)+6a
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