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The next thing that we must acknowledge is that all of the properties for exponents. This includes the more general rational exponent that we haven't looked at yet.
Now the properties of integer explore are valid for this section also then we can see how to deal with the more general rational exponent. In fact there are two different ways of dealing along with them as we'll see. Both of the methods involve via property 2 from the previous section. For reference reason this property is,
(an )m = anm
Thus, let's see how to deal along with a general rational exponent. First we will rewrite the exponent as follows.
b m /n = b(1/n) (m)
In other terms we can think of the exponent like a product of two numbers. We will now use the exponent property illustrated above. Though, we will be using it in the opposite direction than what we did in the earlier section. Also, there are two ways to do it. Here they are following,
b m /n = ( b 1/n ) Or b m/ n =(bm )1/n
By using either of these forms now we can evaluate some more complicated expressions
what is 10+5..
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Determine an actual explicit solution to y′ = t/y; y(2) = -1. Solution : We already identify by the previous illustration that an implicit solution to this IVP is y 2 = t 2 -
In the previous section we looked at the method of undetermined coefficients for getting a particular solution to p (t) y′′ + q (t) y′ + r (t) y = g (t) .....................
conclusion for the shares nd dividends
a²+b²=1 a+b
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